$ evalecho\${${#@}} abc.txt https://stackoverflow.com/questions/2536046/extract-directory-path-and-filename answeredMar 29 '10 at 6:30 ghostdog74
nsoualem@gold: ->echo${FILE%%.*}archive nsoualem@gold: ->echo${FILE%.*}archive.tar nsoualem@gold: ->echo${FILE#*.}tar.gz nsoualem@gold: ->echo${FILE##*.}gz
Extract filename and extension in Bash; 获取文件的扩展名和文件名: filename=$(basename -- "$fullfile") extension="${filename##*.}" filename="${filename%.*}" How to determine function name from inside a function 怎么得到 function 函数的名字; ...
a folderc folder 我使用了以下基于I want to extract all .zip files in a given directory in temp usingpowershell的代码Get-ChildItem $foldername -Filter *.zip | Expand-Archive -Destin 浏览20提问于2019-03-22得票数 0 回答已采纳 1回答 试图解压缩文件夹会导致错误。 在下面的C#代码中,我...
forfilein*.txt;do# extract partsofthe filename to be differently formattedwitha regex match[[$...
1 脚本$ cat autoex.sh #! /usr/bin/bash ex() { if [[ -z $1 ]] ; then echo "Pls input filename to extract" elif [[ -f $1 ]] ; then case $1 in *.tar) tar xvf $1 ;; *.tbz2) tar xvf $1 ;; *.tgz) …
# Shortest.>file# Longer alternatives::>fileecho-n >fileprintf''>file 提取两个标记之间的线条 示例功能: extract() {# Usage: extract file "opening marker" "closing marker"whileIFS=$'\n'read-r line;do[[$extract&&$line!="$3"]] &&printf'%s\n'"$line"[[$line=="$2"]] && extract=...
*.zip) unzip $filename;; *.Z) uncompress $filename;; *) echo "No extract option for $filename" esac 如果提供给脚本的文件扩展名与脚本已知的扩展名都不匹配,那么会发出 “No extract option for $filename” 的消息。如果缺少你使用的任何存档类型,只需将它们与所需的提取命令一起添加即可。
printf '' >file 1. 2. 3. 4. 5. 6. 7. 提取两个标记之间的线条 示例功能: extract() { # Usage: extract file "opening marker" "closing marker" while IFS=$'\n' read -r line; do [[ $extract && $line != "$3" ]] &&
printf "Directory name to extract this file is: %s.\n" $dirname dirfullpath="$UNZIPDIR/$dirname" printf "Directory full path to extract this file is:%s.\n" $dirfullpath mkdir "$dirfullpath" unzip $zip -d $dirfullpath printf "\n\n" ...