Check if the directory still exists The -d operator allows you to test if a file is a directory. For example, to check if the /etc/filetocheck directory exists, you can use: NOTE: You can also use double bracket
directory="./BashScripting" # bash check if directory exists if [ -d $directory ]; then echo "Directory exists" else echo "Directory does not exists" fi 1. 2. 3. 4. 5. 6. 7. 8. 9. 9.2. Nested if/else #!/bin/bash # Declare variable choice and assign value 4 choice=4 # Pr...
执行命令区域，否则 不进入循环，介绍while 命令 行3，执行命令区域，这些命令中，Bash，Unix shell的...
Here you try to regularly kill (TERM signal) the process nicely after 10.0 seconds after it has started. If it's still running after 20.0 seconds, then send a KILL signal (kill -9). If in doubt, check which signals are supported in your system (kill -l, for example). If this isn'...
How to check if a directory exists? How to check if a command succeeds or failed? How to do string comparison and check if a string equals to a value? How to check if a string is in an array? How to use the Bash ternary operator? How to negate an if condition in a Bash if sta...
echo "You are not Alice." fi Example 3: File Check #!/bin/bash file_path="/path/to/file.txt" if [ -f "$file_path" ] then echo "File exists." else echo "File does not exist." fi Compound Condition You can combine multiple conditions using logical operators like && (AND) and ...
mkdir:Make Directory(创建目录) touch:touch man:Manual su:Swith user(切换用户) cd:Change directory ls:List files mkfs:Make file system fsck:File system check uname:Unix name lsmod:List modules mv:Move file cp:Copy file ln:Link files
if [ ! -z err−o!−eapk ]; then 会报出-e无法找到的错误; 而if [ ! -z err]||[!−eapk ]; then 没问题; 整数比较 : -eq 等于,如:if [ "a"−eq"b" ] -ne 不等于,如:if [ "a"−ne"b" ] -gt 大于,如:if [ "a"−gt"b" ] ...
-u filename Check if file set-ser-id bit is set -w filename 检查文件是否可写 -x filename 检查文件是否可执行 例子 [abc@localhost ~]$ vi #!/bin/bash # this is a test file exist ? yes/no file="./testtest.txt" if [ -e $file ]; then echo "File exists!" else echo "File d...
Check if string contains a sub-stringUsing a test:if [[ $var == *sub_string* ]]; then printf '%s\n' "sub_string is in var." fi # Inverse (substring not in string). if [[ $var != *sub_string* ]]; then printf '%s\n' "sub_string is not in var." fi # This works ...