/* Delete the character under the cursor. Given a numeric argument, kill that many characters instead. */intrl_delete(count, key)intcount, key; {intxpoint;if(count <0)return(_rl_rubout_char (-count, key));if(rl_point == rl_end) { rl_ding ();return-1; }if(count >1|| rl_ex...
How to check if a directory exists? How to check if a command succeeds or failed? How to do string comparison and check if a string equals to a value? How to check if a string is in an array? How to use the Bash ternary operator? How to negate an if condition in a Bash if sta...
#Take the filename from the command-line argument filename=$1 #Check whether the argument is missing or not if["$filename"!=""];then #Check whether the file exists or not using the -f operator if[[-f"$filename"]];then echo"File exists." ...
Here the “-z” option is used with the “test” command to check if the input argument is an empty string or not. The script will output an error message and exit with a status code of 1 if the input argument is an empty string. Otherwise, the script will continue executing, below ...
if [ -e $file ]; then echo "File exists" else echo "File does not exists" fi 1. 2. 3. 4. 5. 6. 7. Similarly for example we can use while loop to check if file does not exists. This script will sleep until file does exists. Note bash negator "!" which negates the -e ...
# The shift command removes one argument from the list of # command line arguments. shift shift # $* contains now all the files: for file in $*; do if [ -f "$file" ] ; then newfile=`echo "$file" | sed "s/${OLD}/${NEW}/g" ...
Declare a local variable 'num' to store the argument passed to the function. Declare another local variable 'result' and initialize it to 1. Check if 'num' is negative. If it is, we print an error message and exit the script.
Write a Bash script that checks if a directory named "workarea" exists and creates it if it doesn't. Code: #!/bin/bash# Check if the directory "workarea" existsif[!-d"workarea"];then# If the directory doesn't exist, create itmkdirworkareaecho"Directory 'workarea' created successfully."...
Check if string contains a sub-stringUsing a test:if [[ $var == *sub_string* ]]; then printf '%s\n' "sub_string is in var." fi # Inverse (substring not in string). if [[ $var != *sub_string* ]]; then printf '%s\n' "sub_string is not in var." fi # This works ...
The example shows how to exit an infiniteforloop using abreak. TheBash if statementhelps check the value for each integer and provides thebreakcondition. This terminates the script when an integer reaches the value ten. To exit a nested loop and an outer loop, usebreak 2. ...