especially given this is a tree related problem. What we can do is get the height of the left sub tree, compared with the right sub tree, then do the logics to see if it’s balanced or not. If at certain level either the left or right sub tree is not balanced, then entire Tree ...
leetcode 39:balanced-binary-tree 题目描述本题要求判断给定的二叉树是否是平衡二叉树平衡二叉树的性质为: 要么是一棵空树,要么任何一个节点的左右子树高度差的绝对值不超过 1。一颗树的高度指的是树的根节点到所有节点的距离中的最大值。代码如下:1 int maxDepth(TreeNode* root) 2 { 3 if(root == ...
Can you solve this real interview question? Balanced Binary Tree - Given a binary tree, determine if it is height-balanced. Example 1: [https://assets.leetcode.com/uploads/2020/10/06/balance_1.jpg] Input: root = [3,9,20,null,null,15,7] Output: tru
LeetCode—110. Balanced Binary Tree 题目 https://leetcode.com/problems/balanced-binary-tree/description/ 判断一棵二叉树是否是平衡二叉树。 平衡二叉树指的是,两棵子树的任一节点的深度相差不超过1. 思路及解法 首先写一个函数用来得到每一个子树的深度,然后递归调用原函数,判断两棵子树的深度差... ...
LeetCode 110 Balanced Binary Tree(平衡二叉树)(*) LeetCode 110 Balanced Binary Tree(平衡二叉树)(*) 翻译 (高度是名词不是形容词…… 对于这个问题。一个高度平衡二叉树被定义为: 这棵树的每一个节点的两个子树的深度差不能超过1。 原文 分析 这道题。我觉得非常有意义,考察得也非常全面。我觉得的...
https://leetcode.com/submissions/detail/40087813/ Total Accepted: 72203 Total Submissions: 225370 Difficulty: Easy 题目描述 Given a binary tree, determine if it is height-balanced. For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of...
LeetCode 110. Balanced Binary Tree Description Given a binary tree, determine if it is height-balanced. For this problem, a height-balanced binary tree is defined as: a binary tree in which the depth of the two subtrees of every node never differ by more than 1. Example 1: Given the ...
# class TreeNode(object): # def __init__(self, x): # self.val = x # self.left = None # self.right = None class Solution(object): def isBalanced(self, root): """ :type root: TreeNode :rtype: bool """ if root == None: return True left, right = self.height(root) if ...
For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the two subtrees of every node never differ by more than 1. 题目分析: 平衡二叉树:(1)要么为空,要么左右子树的深度差值不超过1;(2)左右两个子树都是一棵平衡二叉树,即子树也都要都满足条件(1...
package leetcode /** * Definition for a binary tree node. * type TreeNode struct { * Val int * Left *TreeNode * Right *TreeNode * } */ func isBalanced(root *TreeNode) bool { if root == nil { return true } leftHight := depth(root.Left) rightHight := depth(root.Right) retur...