another solution nums.sort(function(a, b){return a-b}); let secLargest = nums[nums.length-2]; let largest = nums[nums.length-1]; for (let i = nums.length-1; i >= 0; i--){ if(nums[i-1] == nums[i]) { largest = nums[i-1]; secLargest = nums[i-2]; } else { sec...
vibhavp6/Vibhav-Leetcode-GeeksForGeeks-HackerRankmain 1 Branch 0 Tags Code Folders and filesLatest commit vibhavp6 Added Solution - GfG to GitHub f0c5aeb· Jul 18, 2024 History694 Commits 0div-idbig-omega-company-tagsdiv-idbig-omega-topbardiv-classcompanytagscontainer-styleoverflow-x-scroll-...
"error: subscripted value is neither array nor pointer nor, So to write the program I made a vector of the type node as in: estados=malloc (n*sizeof (node)); and the idea was to use each position of the node vector to … Value with C-subscript is not a vector, pointer or arra...
Given an array of integersnumsand an integertarget, return indices of the two numbers such that they add up totarget. You may assume that each input would have exactly one solution, and you may not use the same element twice. You can return the answer in any order. For example: Input...
Time Complexity: O((N+M)log(N+M)). Given N is the number of elements in arr1 and M is the number of elements in arr2 . Space Complexity: O(N+M) Solution 02 Pseudocode Credits: GeeksForGeeks Create an array arr3 of length/size arr1 + arr2 . Simultaneously traverse arr1 and ar...