Given an array, we have to find the second largest number in the array using the class and object approach. Example: Input: array[0]:1 array[1]:2 array[2]:44 array[3]:3 array[4]:5 Output: Second Largest Number i
public class FindSecondLargestMain { public static void main(String args[]) { int[] arr1={7,5,6,1,4,2}; int secondHighest=findSecondLargestNumberInTheArray(arr1); System.out.println("Second largest element in the array : "+ secondHighest); } public static int findSecondLargestNumberIn...
int[] myArray = { 1, 4, 7, 1, 2, 6, 23 };; int largest = int.MinValue; int second = int.MinValue; foreach (int i in myArray) { if (i > largest) { second = largest; largest = i; } else if (i > second) second = i; } ...
JavaScript Code: // Define a function named Second_Greatest_Lowest that finds the second smallest and second largest numbers in an arrayfunctionSecond_Greatest_Lowest(arr_num){// Sort the array in ascending order using a custom comparison functionarr_num.sort(function(x,y){returnx-y;});// ...
Find ith largest number in an array Question: Given an integer array, find out the second largest integer. Analysis: Sort the array (ascending) first. The second largest will be the last but one? Too young, too simple, sometimes naive. It will not work if there are duplicated times. E...
second_largest_values = nums[indices, np.arange(nums.shape[1])]: This line creates a new array second_largest_values by indexing nums using the row indices in indices and column indices created by np.arange(nums.shape[1]), which returns an array of integers from 0 to the number of col...
Rearrange Array to Order: Smallest, Largest, 2nd Smallest, 2nd Largest Using C++C++Server Side ProgrammingProgramming We are given an array; we need to arrange this array in an order that the first element should be a minimum element, the second element should be a maximum element, ...
// Scala program to find the second largest element // from the array object Sample { def main(args: Array[String]) { var IntArray = Array(10,50,40,20,30) var count:Int=0 var large1:Int=0 var large2:Int=0 large1=IntArray(0) while(count<IntArray.size) { if (large1 < Int...
IfAis complex, thenmax(A)returns the complex number with the largest magnitude. If magnitudes are equal, thenmax(A)returns the value with the largest magnitude and the largest phase angle. IfAis a scalar, thenmax(A)returnsA. IfAis a 0-by-0 empty array, thenmax(A)is as well. ...
Any value less than x0 will be placed in the first bin; any value greater than or equal to x0 but less than x1 will be placed in the second bin; and so on. Thus, the generated bins will have thresholds.length + 1 bins. See bin thresholds for more information....