In this program, we will read an integer number and check number is Armstrong or not, and print an appropriate message on the console screen. Program/Source Code: The source code tofind the given number is Armstrong or not using theforloopis given below. The given program is compiled and...
In this program, you'll learn to check whether a given number is armstrong number or not. You'll learn to do this by using a while loop in Kotlin.
Python program to check Armstrong number using object oriented approach# Define a class for Checking Armstrong number class Check : # Constructor def __init__(self,number) : self.num = number # define a method for checking number is Armstrong or not def isArmstrong(self) : # copy num ...
Steps to Implement the Program in Java Input the Range:Get two integers from the user that define the range. Check Each Number:Loop through each number in the range and check if it is an Armstrong number. Count Digits:For each number, count its digits to determine the power for each digi...
for (loop = 1; loop <= r; loop=loop+1) prime = prime * num; return prime; } Output of above program How it works: This table Shows Exactly What Occurs at each iteration of the while loop (assuming the num = 1634): To print out all armstrong numbers between 1 and 1000. ...
For example, myList.length returns 10 Initializing Arrays Using a loop: for (int i = 0; i < myList.length; i++) myList[i] = i; Declaring, creating, initializing in one step: double[] myList = {1.9, 2.9, 3.4, 3.5}; This shorthand syntax must be in one statement. ...
Note: In the above program, the cube of a number could be calculated using anexponent operator**. For example,sum += remainder ** 3; Example 2: Check Armstrong Number of n Digits // program to check an Armstrong number of n digits// take an inputconstnumber = prompt("Enter a positiv...
{ // copying the value of the parameter // into data members number = n; // declaring int type variables for indexing // and storing result int index, remain, result = 0; // while loop for manipulating the number while (number) { // remain contains the last element of the number ...