Here's the equivalent Java code: Java Program to Check Armstrong Number Example 2: Check Armstrong number for n digits fun main(args: Array) { val number = 1634 var originalNumber: Int var remainder: Int var result = 0 var n = 0 originalNumber = number while (originalNumber != 0) {...
// GoLang program to find the given number is Armstrong or not// using "for" loop.packagemainimport"fmt"funcmain() {varnumint=0varremint=0varresint=0vartmpint=0fmt.Print("Enter Number: ") fmt.Scanf("%d",&num) tmp = numfornum >0{ rem = num%10res = res+(rem*rem*rem) num...
Python program to check Armstrong number using object oriented approach# Define a class for Checking Armstrong number class Check : # Constructor def __init__(self,number) : self.num = number # define a method for checking number is Armstrong or not def isArmstrong(self) : # copy num ...
Steps to Implement the Program in Java Input the Range:Get two integers from the user that define the range. Check Each Number:Loop through each number in the range and check if it is an Armstrong number. Count Digits:For each number, count its digits to determine the power for each digi...
printf ("\nNumber %d is armstrong number", num); } } getch(); } OUTPUT: Explanation: In this program, we have to find all Armstrong numbers between 1 and 1000. For this, we firstly initialize (sum = 0) and temp = num = 1. Then we apply modulus operator(%) and various other ...
Once an array is created, its size is fixed. It cannot be changed. You can find its size using arrayVariable.length For example, myList.length returns 10 Initializing Arrays Using a loop: for (int i = 0; i < myList.length; i++) ...
Finally, the sum is compared with the number entered by the user. If the sum and the number are equal, the number is an Armstrong number. Note: In the above program, the cube of a number could be calculated using anexponent operator**. For example,sum += remainder ** 3; ...
// declaring int type variables for indexing // and storing result int index, remain, result = 0; // while loop for manipulating the number while (number) { // remain contains the last element of the number remain = number % 10; // result contains the cube of remain added to it r...