# Python program to check if the number provided by the user is an Armstrong number or not # take input from the user num = int(input("Enter a number: ")) # initialize sum sum = 0 # find the sum of the cube of each digit temp = num while temp > 0: digit = temp % 10 sum...
It's an Armstrong Number. Cubing numbers:3*3*3 + 7*7*7 + 1= 371 (Armstrong Number) Conclusion We will go through lots of tricky logic and a simple one with Visual Studio in Python. We see it's very easy to implement it. Read more articles onPython: Diving Into Python: Chapter 1...
最后,如果发现总和等于原始数,则称为阿姆斯特朗数(Armstrong)。...number") else: print(num,"is not an Armstrong number") ▍50、用一行Python代码,从给定列表中取出所有的偶数和奇数 a = [1,2,3,4,5,6,7,8,9,10 1.5K30 如何从列表中获取元素 有两种方法可用于从列表中获取元素,这涉及到两个命令,...
Python program to check Armstrong number using object oriented approach# Define a class for Checking Armstrong number class Check : # Constructor def __init__(self,number) : self.num = number # define a method for checking number is Armstrong or not def isArmstrong(self) : # copy num ...
Suppose thenumber is 153. Then, (153 % 10 = 3 ** 3) + is_armstrong(153 // 10 = 15, 3). Here, the is_armstrong() method calls itself,so again, the same code block executes for thedigit 15and so on. This is how we can findArmstrong’s number using recursion in Python. ...
fmt.Printf("Number is not armstrong") } } Output: RUN 1: Enter Number: 153 Number is armstrong RUN 2: Enter Number: 123 Number is not armstrong Explanation: In the above program, we declare the packagemain. Themainpackage is used to tell the Go language compiler that the package must ...
4 digit Armstrong number 1634 = 1^4 + 6^4 + 3^4 + 4^4 Some other example of Armstrong numbers are0, 1, 2, 3, 153, 370, 407, 1634, 8208, etc. In this tutorial, you will learn to write a python program to check whether a number is Armstrong number or not for 3 digits num...
Armstrong number in C or Narcissistic number is an n-digit number equal to the sum of digits raised to the nth power of digits
In this example, you will learn to write a program in JavaScript to check whether a number is an Armstrong number or not.
Let’s check whether 370 is an Armstrong number or not 370 = (3 * 3 * 3) + (7 * 7 * 7) + (0 * 0 * 0) Here, (3 * 3 * 3) = 27 (7 * 7 * 7) = 343 (0 * 0 * 0) = 0 27 + 343 + 0 = 370, which is equal to the given number; hence it is an Armstrong...