# Python program to check if the number provided by the user is an Armstrong number or not # take input from the user num = int(input("Enter a number: ")) # initialize sum sum = 0 # find the sum of the cube of each digit temp = num while temp > 0: digit = temp % 10 sum...
Suppose thenumber is 153. Then, (153 % 10 = 3 ** 3) + is_armstrong(153 // 10 = 15, 3). Here, the is_armstrong() method calls itself,so again, the same code block executes for thedigit 15and so on. This is how we can findArmstrong’s number using recursion in Python. ...
以下是一个Python函数,用于检查一个n位数是否为Armstrong数: 代码语言:txt 复制 def is_armstrong_number(number): # 将数字转换为字符串以便逐位处理 num_str = str(number) n = len(num_str) # 获取数字的位数 # 计算各位数字的n次方之和 sum_of_powers = sum(int(digit) ** n for digit in num...
It's an Armstrong Number. Cubing numbers:3*3*3 + 7*7*7 + 1= 371 (Armstrong Number) Conclusion We will go through lots of tricky logic and a simple one with Visual Studio in Python. We see it's very easy to implement it. Read more articles onPython: Diving Into Python: Chapter 1...
问如何在Python中检查n位数是否为Armstrong数？EN在编程中，我们经常需要检查一个字符是否为数字。这种判断...
实例(Python 3.0+) # Filename : test.py # author by : www.runoob.com # Python 检测用户输入的数字是否为阿姆斯特朗数 # 获取用户输入的数字 num = int(input("请输入一个数字: ")) # 初始化变量 sum sum = 0 # 指数 n = len(str(num)) # 检测 temp = num while temp > 0: digit = ...
Problem4: PerfectNumber.java Problem5: ArmstrongNumbers.java Pyramid.java: (Printing numbers in a pyramid pattern) Write down a program in Java with anested for loop that prints the following output (powers of 2) for any number of lines:Here is a sample run:Enter the number of lines: 8...
Python program to check Armstrong number using object oriented approach# Define a class for Checking Armstrong number class Check : # Constructor def __init__(self,number) : self.num = number # define a method for checking number is Armstrong or not def isArmstrong(self) : # copy num ...
Check N digit Armstrong Number #Python program to check n Digits Armstrong Number #Taking input from user number = int(input("Enter a number: ")) # Declarign and intilizing sum variable result = 0 # Declarign and intilizing number of digits variable n = 0 #coping number in another vari...
Armstrong number in C or Narcissistic number is an n-digit number equal to the sum of digits raised to the nth power of digits