# Python program to check if the number provided by the user is an Armstrong number or not # take input from the user num = int(input("Enter a number: ")) # initialize sum sum = 0 # find the sum of the cube of
Armstrong 数(也称为自幂数)是指一个 n 位数,它的每个位上的数字的 n 次幂之和等于它本身。例如,153 是一个 Armstrong 数,因为 1^3 + 5^3 + 3^3 = 153。下面是一个 Python 程序,用于判断一个数字是否为 Armstrong 数。实例 def is_armstrong_number(num): # 将数字转换为字符串,以便逐个获取每个数...
for number in range(1, 10001): if number < 10: #1-9都为阿姆斯特朗数,直接输出即可 print(number) elif number < 100: n1 = number % 10 #取个位数 n2 = int(number/10 % 10) #取十位数 result = n1**2 + n2**2 if number == result: print(number) elif number < 1000: n1 = number...
Suppose thenumber is 153. Then, (153 % 10 = 3 ** 3) + is_armstrong(153 // 10 = 15, 3). Here, the is_armstrong() method calls itself,so again, the same code block executes for thedigit 15and so on. This is how we can findArmstrong’s number using recursion in Python. ...
Armstrong Number In Python What Is An Armstrong Number? Program To Check Armstrong Number Of N Digits Python中的阿姆斯特朗数 什么是阿姆斯特朗号? 既然您知道阿姆斯壮数字是什么,让我们探索如何用Python编写同样的程序。 用最简单的术语来说,阿姆斯特朗数字可以定义为整数,其数字的立方之和等于数字本身。阿姆斯特朗...
以下是一个Python函数,用于检查一个n位数是否为Armstrong数: 代码语言:txt 复制 def is_armstrong_number(number): # 将数字转换为字符串以便逐位处理 num_str = str(number) n = len(num_str) # 获取数字的位数 # 计算各位数字的n次方之和 sum_of_powers = sum(int(digit) ** n for digit in num...
It's an Armstrong Number. Cubing numbers:3*3*3 + 7*7*7 + 1= 371 (Armstrong Number) Conclusion We will go through lots of tricky logic and a simple one with Visual Studio in Python. We see it's very easy to implement it.
假设我们有一个整数列表,我们需要从中筛选出所有的Armstrong数字。以下是一个Python示例代码: 代码语言:txt 复制 def is_armstrong(num): # 将数字转换为字符串,以便逐位处理 str_num = str(num) n = len(str_num) # 计算各位数字的n次方之和 sum_of_powers = sum(int(digit) ** n for digit in str...
153 = 1*1*1 + 5*5*5 + 3*3*3 // 153 is an Armstrong number. Visit this page to learn how you can check whether a number is an Armstrong number or not in Python. Source Code # Program to check Armstrong numbers in a certain interval lower = 100 upper = 2000 for num in ran...
Problem4: PerfectNumber.java Problem5: ArmstrongNumbers.java Pyramid.java: (Printing numbers in a pyramid pattern) Write down a program in Java with anested for loop that prints the following output (powers of 2) for any number of lines:Here is a sample run:Enter the number of lines: 8...