# Python program to check if the number provided by the user is an Armstrong number or not # take input from the user num = int(input("Enter a number: ")) # initialize sum sum = 0 # find the sum of the cube of each digit temp = num while temp > 0: digit = temp % 10 sum...
Python program to check Armstrong number using object oriented approach# Define a class for Checking Armstrong number class Check : # Constructor def __init__(self,number) : self.num = number # define a method for checking number is Armstrong or not def isArmstrong(self) : # copy num ...
In this Python tutorial, you will learn how to find Armstrong numbers using recursion in Python. Generally, the Armstrong number is a way to practice looping, conditions, etc., to gain programming skills and improve logical thinking. Although the Armstrong number is not actually used in real-ti...
print(num,"is an Armstrong number") else: print(num,"is not an Armstrong number") Open up Visual Studio After that open a Visual Studio project withPython, The program Will try with 2 numbers. Let's try 346, Now 371, It's an Armstrong Number. Cubing numbers:3*3*3 + 7*7*7 + ...
/usr/bin/python3 #-*- coding:UTF-8 -*- print("10000以内的阿姆斯特朗数有:") for number in range(1, 10001): if number < 10: #1-9都为阿姆斯特朗数,直接输出即可 print(number) elif number < 100: n1 = number % 10 #取个位数 n2 = int(number/10 % 10) #取十位数...
3 digit Armstrong number 3^3 + 7^3 + 0^3 = 370 4 digit Armstrong number 1634=1^4+6^4+3^4+4^4 Some other example of Armstrong numbers are0, 1, 2, 3, 153, 370, 407, 1634, 8208, etc. In this tutorial, you will learn to write a python program to check whether a number ...
LongestCommonPrefix.java: Write a program in Java 代写Pyramid Interests PerfectNumber ArmstrongNumbers that prompts the user to enter two stringsand display the largest common prefix of the two strings. If there are no common prefixbetween the two entered strings display a message which tells the...
实例(Python 3.0+) # Filename : test.py # author by : www.runoob.com # Python 检测用户输入的数字是否为阿姆斯特朗数 # 获取用户输入的数字 num = int(input("请输入一个数字: ")) # 初始化变量 sum sum = 0 # 指数 n = len(str(num)) # 检测 temp = num while temp > 0: digit = ...
printf ("\nNumber %d is armstrong number", num); } } getch(); } OUTPUT: Explanation: In this program, we have to find all Armstrong numbers between 1 and 1000. For this, we firstly initialize (sum = 0) and temp = num = 1. Then we apply modulus operator(%) and various other ...
Program to print Armstrong numbers between a range in Java importjava.util.Scanner;publicclassGenerateArmstrongNumber{publicstaticvoidmain(Stringargs[]){intn,n1,n2,i,rem,temp,count=0;Scanner scan=newScanner(System.in);/* enter the interval between which number is printed */System.out.print("En...