# Python program to check if the number provided by the user is an Armstrong number or not # take input from the user num = int(input("Enter a number: ")) # initialize sum sum = 0 # find the sum of the cube of
Python program to check Armstrong number using object oriented approach# Define a class for Checking Armstrong number class Check : # Constructor def __init__(self,number) : self.num = number # define a method for checking number is Armstrong or not def isArmstrong(self) : # copy num ...
153 = 1*1*1 + 5*5*5 + 3*3*3 // 153 is an Armstrong number. Visit this page to learn how you can check whether a number is an Armstrong number or not in Python. Source Code # Program to check Armstrong numbers in a certain interval lower = 100 upper = 2000 for num in ran...
print(num,"is an Armstrong number") else: print(num,"is not an Armstrong number") Open up Visual Studio After that open a Visual Studio project withPython, The program Will try with 2 numbers. Let's try 346, Now 371, It's an Armstrong Number. Cubing numbers:3*3*3 + 7*7*7 + ...
In this Python article, you learnedHow to Find Armstrong Number Using Recursion in Pythonwith the practical example where we are taking user input to make the program dynamic. You may also like to read: Bijay Kumar I am Bijay Kumar, aMicrosoft MVPin SharePoint. Apart from SharePoint, I st...
procedure armstrong : number check = number rem = 0 WHILE check IS NOT 0 rem ← check modulo 10 sum ← sum + (rem)3 divide check by 10 END WHILE IF sum equals to number PRINT armstrong ELSE PRINT not an armstrong END IF end procedure ...
/usr/bin/python3 #-*- coding:UTF-8 -*- print("10000以内的阿姆斯特朗数有:") for number in range(1, 10001): if number < 10: #1-9都为阿姆斯特朗数,直接输出即可 print(number) elif number < 100: n1 = number % 10 #取个位数 n2 = int(number/10 % 10) #取十位数...
LongestCommonPrefix.java: Write a program in Java 代写Pyramid Interests PerfectNumber ArmstrongNumbers that prompts the user to enter two stringsand display the largest common prefix of the two strings. If there are no common prefixbetween the two entered strings display a message which tells the...
实例(Python 3.0+) # Filename : test.py # author by : www.runoob.com # Python 检测用户输入的数字是否为阿姆斯特朗数 # 获取用户输入的数字 num = int(input("请输入一个数字: ")) # 初始化变量 sum sum = 0 # 指数 n = len(str(num)) # 检测 temp = num while temp > 0: digit = ...
printf("\nNumber %d is armstrong number", num); } } getch(); } OUTPUT: Explanation: In this program, we have to find all Armstrong numbers between 1 and 1000. For this, we firstly initialize (sum = 0) and temp = num = 1. Then we apply modulus operator(%) and various other ope...