Ambiguous column name 'AddedDate'. 原来就是Forums表中和Post表中具有相同的列AddedDate,通过as 方式改写就可以解决了 SET ANSI_NULLS ON GO SET QUOTED_IDENTIFIER ON GO IF NOT EXISTS (SELECT * FROM sys.objects WHERE object_id = OBJECT
Ambiguous column name 'AddedDate'. 原来就是Forums表中和Post表中具有相同的列AddedDate,通过as 方式改写就可以解决了 SET ANSI_NULLS ON GO SET QUOTED_IDENTIFIER ON GO IF NOT EXISTS (SELECT * FROM sys.objects WHERE object_id = OBJECT_ID(N'[dbo].[tbh_Forums_GetThreadByID]') AND type in (N...
1. "ambiguous column name"错误的含义 "ambiguous column name"错误,直译为“模棱两可的列名”,是指在SQL查询中,由于查询涉及多个表,而这些表中存在同名的列,但没有明确指定是哪个表的列,导致数据库无法确定引用的是哪个表的列,从而引发的错误。 2. 可能导致"ambiguous column name"错误的常见场景 多表连接查询...
According toBURLESON, A column name used in a join exists in more than one table and is thus referenced ambiguously. Ambiguous Column Error in Subquery – Here’s Resolution SriniJune 26, 2017 How I fixed? In a join, any column name that occurs in more than one of the tables must be ...
Power BI services, connected to Snowflake, generates SQL that triggers an error: " Unable to connect to the data source ODBC: ERROR [42601] SQL compilation error: ambiguous column name 'name'." The tables and attributes in question are DEALS.name, SCOPES.name, SUB_SCOPES.name, and QUESTIO...
CREATE TABLE t ( c BOOL, CHECK (c), INDEX (c) WHERE c ); INSERT INTO t VALUES (true); -- ERROR: column reference "c" is ambiguous (candidates: <anonymous>.c) Another case of this (c must be the PK for this to reproduce): CREATE TABLE t ( c BOOL PRIMARY KEY, CHECK (c),...
limit 0, 10]; Column 'created_by' in where clause is ambiguous; nested exception is com.mysql.jdbc.exceptions.jdbc4.MySQLIntegrityConstraintViolationException: Column 'created_by' in where clause is ambiguous 原因: 说明SQL语句中有重复的created_by功能调用,并且在Mapper文件中,多表关联查询中有相同的...
from ibdhl A left join ibdhldetail B ON IhlId=B.IhlId 在 on 后面，应该要写成 A.IhlId=B.IhlId 。因为这两个字段名是一样的，系统无法判断你是从什么表获取数据，所以就 ambiguous 了。
I'll look into this tomorrow but since the update to 2.2.0 I've noticed this issue on sentry; ProgrammingError at /app/model/1/ column reference "id" is ambiguous LINE 1: SELECT (CASE WHEN id='1' THEN 0 END) AS "ordering", "... It compla...
from arrivage a join lot l on l.id = a.lot_id and l.numero ='20230620V327'; The result is displayed You try to edit and modify a value, and the you save it. It returns this message SQL Error [42702]: ERROR: column reference "id" is ambiguous ...