【LeetCode】33.Linked List — Add Two Numbers两数相加 You are given two non-empty linked lists representing two non-negative integers. The digits are stored in reverse order and each of their nodes contain a single
6 参考 Add Two Numbers -- LeetCode LeetCode:Add Two Numbers Add Two Numbers leetcode java [LeetCode] Add Two Numbers, Solution
题目 You are given two non-empty linked lists representing two non-negative integers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list. You may assume the two numbers do not contain any leading zero...
# Definition for singly-linked list. # class ListNode: # def __init__(self, val=0, next=None): # self.val = val # self.next = next class Solution: def addTwoNumbers(self, l1: Optional[ListNode], l2: Optional[ListNode]) -> Optional[ListNode]: # 哨兵结点,方便后续处理 head_pre =...
# Definition for singly-linked list. # class ListNode: # def __init__(self, val=0, next=None): # self.val = val # self.next = next class Solution: def addTwoNumbers(self, l1: ListNode, l2: ListNode) -> ListNode: link1 = l1 ...
leetcode算法—两数相加 Add Two Numbers 关注微信公众号:CodingTechWork,一起学习进步。 题目 Add Two Numbers: You are given two non-empty linked lists representing two non-negative integers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two ...
LeetCode: 2. Add Two Numbers LeetCode: 2. Add Two Numbers 题目描述 You are given two non-empty linked lists representing two non-negative integers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list...
3 输入与输出：/*** Definition for singly-linked list.* struct ListNode {* int val;* ListNode *next;* ListNode(int x) : val(x), next(NULL) {}* };*/class Solution {public: ListNode* addTwoNumbers(ListNode* l1, ListNode* l2) { }};4 解决思路：从表头开始相加，记录每次相加...
方法二:遍历两个list,直接按位计算,记录是否进位# Definition for singly-linked list. # class ListNode(object): # def __init__(self, x): # self.val = x # self.next = None class Solution(object): def addTwoNumbers(self, l1, l2): """ :type l1: ListNode :type l2: ListNode :rtype...
*/classSolution{public:ListNode*addTwoNumbers(ListNode*l1,ListNode*l2){ListNode*rst=newListNode(0);ListNode*p=rst,*q;int carry=0,oneSum;while(l1!=NULL&&l2!=NULL){oneSum=l1->val+l2->val+carry;q=newListNode(oneSum%10);p->next=q;p=p->next;carry=oneSum/10;l1=l1->next;l2=l2->nex...