代码(Python3) # Definition for singly-linked list. # class ListNode: # def __init__(self, val=0, next=None): # self.val = val # self.next = next class Solution: def addTwoNumbers(self, l1: Optional[ListNode], l2: Optional[ListNode]) -> Optional[ListNode]: # 哨兵结点,方便后续处...
最终成绩是: 第二种方法是直接在链表上面进行操作,两个数直接相加,后面再进行处理 # Definition for singly-linked list. # class ListNode: # def __init__(self, val=0, next=None): # self.val = val # self.next = next class Solution: def addTwoNumbers(self, l1: ListNode, l2: ListNode) -...
class Solution(object): def addTwoNumbers(self, l1, l2): """ :type l1: ListNode :type l2: ListNode :rtype: ListNode """<br>#把链表值放进列表中。方便之后迭代 l1a = [] l2a = [] result = [] l1a.append(l1.val) l2a.append(l2.val) loop = ListNode(0) loop1 = l1 loop2 = ...
AI代码解释 publicstaticListNodeaddTwoNumbers(ListNode l1,ListNode l2){// 边界条件判断if(l1==null){returnl2;}elseif(l2==null){returnl1;}ListNode head=newListNode(0);ListNode point=head;int carry=0;while(l1!=null&&l2!=null){int sum=carry+l1.val+l2.val;ListNode rest=newListNode(sum%10)...
Leetcode 解题 Add Two Numbers Python 原题:You are given two linked lists representing two non-negative numbers.The digits are stored in reverse order and each of their nodes contain a single digitAdd the two numbers and return it as a linked list...
EasyLeetCode 02,两数相加(Add Two Numbers) 作者| 梁唐 大家好,我是梁唐。 题意 题意很简单,给定两个非空的链表。用逆序的链表来表示一个整数,要求我们将这两个数相加,并且返回一个同样形式的链表。 除了数字0之外,这两个数都不会以0开头,也就是没有前导0。
leetcode算法—两数相加 Add Two Numbers 关注微信公众号:CodingTechWork,一起学习进步。 题目 Add Two Numbers: You are given two non-empty linked lists representing two non-negative integers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two ...
【LeetCode】2. Add Two Numbers 两数相加 作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 个人公众号:负雪明烛 本文关键词:两数相加,链表,求加法,题解,leetcode, 力扣,python, c++, java 目录 题目描述
class Solution { public: ListNode *addTwoNumbers(ListNode *l1, ListNode *l2) { // Start typing your C/C++ solution below if(l1 == NULL && l2 == NULL) { return NULL; } ListNode *retList = new ListNode(0); ListNode *tmpList = retList; ...
javapythongorustjsp 算法思路相同,都是使用dummy节点和cur指针,两两交换链表节点,并返回dummy.next作为结果。 疯狂的KK 2023/05/16 9910 leetcode 2 Add two numbers addleetcodenumbers public class Solution { public ListNode addTwoNumbers(ListNode l1, ListNode l2) { ListNode dummy = new ListNode(-1);...