Input: (2 -> 4 -> 3) + (5 -> 6 -> 4) Output: 7 -> 0 -> 8 我的第一种解法 就是建立一个ListNode,保存每位数相加的和,别忘记用一个变量来存储进位。 将每次计算得到的数字用ListNode连接在一次,保存返回就可以了。 classSolution {public: ListNode* addTwoNumbers(ListNode* l1, ListNode*l2...
https://leetcode.com/problems/add-two-numbers/ https://leetcode.com/problems/add-two-numbers/discuss/997/c%2B%2B-Sharing-my-11-line-c%2B%2B-solution-can-someone-make-it-even-more-concise LeetCode All in One 题目讲解汇总(持续更新中...)...
(LeetCode) T2. Add Two Numbers Problem:Youaregiventwonon-emptylinkedlistsrepresentingtwonon-negativeintegers.Thedigitsarestoredinreverseorderandeachoftheirnodescontainasingledigit.Addthetwonumbersand 智能推荐 2. Add Two Numbers class Solution { public: ListNode* addTwoNumbers(ListNode* l1, ListNode* ...
val=0, next=None):# self.val = val# self.next = nextclassSolution:defaddTwoNumbers(self,l1:ListNode,l2:ListNode)->ListNode:list1=[]while(l1!=None):list1.append(l1.val)l1=l1.nextlist2=[]while(l2!=None):list2.append(l2.val)l2=l2.nextl1=list1l2=list2output=[]iflen(l1)>=len...
class Solution { public: ListNode *addTwoNumbers(ListNode *l1, ListNode *l2) { // Start typing your C/C++ solution below if(l1 == NULL && l2 == NULL) { return NULL; } ListNode *retList = new ListNode(0); ListNode *tmpList = retList; ...
public class Solution { /* * 方法1 */ public static ListNode addTwoNumbers(ListNode l1,ListNode l2) { //如果都为空 直接返回不为空的一个参数 如果都未空 则返回空 if(l1 == null || l2 == null){ return l1 == null ?(l2 == null ?null:l2):l1; ...
Leetcode 2. Add Two Numbers You are given two non-empty linked lists representing two non-negative integers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list....
本题是 Leetcode Top 100 liked questions 中的第二题。 2. Add Two Numbers Medium You are given two non-empty linked lists representing two non-negative integers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a...
[LeetCode] Add Two Numbers(stored in List) 首先,演示一个错误的reverList class Solution { public: ListNode* reverse(ListNode* root) { if(NULL == root) return NULL; ListNode* pCur = root; ListNode* pNext = root->next; while(pNext) { pNext = pNext->next; pCur->next->next = pCur...
My Solution 代码语言:javascript 代码运行次数:0 classSolution{public:ListNode*addTwoNumbers(ListNode*l1,ListNode*l2){ListNode*p=l1;ListNode*q=l2;int sum=0;ListNode*sentinel=newListNode(0);ListNode*d=sentinel;if((p==NULL)&&(q!=NULL)){returnq;}if((p!=NULL)&&(q==NULL)){returnp;}do{if(...