* int val; * struct ListNode *next; * }; */structListNode*addTwoNumbers(structListNode*l1,structListNode*l2){structListNode*l=(structListNode*)malloc(sizeof(structListNode));l->next=NULL;structListNode*p=l;int flag=0;while(l1||l2){int temp=(l1!=NULL?l1->val:0)+(l2!=NULL?l2->val...
}publicListNode AddTwoNumbers(ListNode l1, ListNode l2) { ListNode c1=l1; ListNode c2=l2; ListNode head=newListNode(0); ListNode p=head;intsum =0;while(c1!=null||c2!=null) { sum/=10;if(c1!=null) { sum+=c1.val; c1=c1.next; }if(c2!=null) { sum+=c2.val; c2=c2.next; }...
ListNode* addTwoNumbers(ListNode* l1, ListNode*l2) {intcur=0;intc=0; ListNode* root=newListNode(0); ListNode* res=root;while(l1 &&l2) { res->next=newListNode(0); res=res->next; cur=c+l1->val+l2->val; c=cur/10; cur=cur%10; res->val=cur; l1=l1->next; l2=l2->next; }...
l2=l2.nextelse:b=0ddsum=a+b+flag flag=ddsum/10ret.val=ddsum%10ifl1:mark=1ifl2:mark=1ifflag:mark=1ifmark:ret.next=ListNode(0)ret=ret.nextreturnddif__name__=='__main__':a=Solution()b=a.initData('5')c=a.initData('5')a.printNode(b)a.printNode(c)d=a.addTwoNumbers(b...
Add Two Numbers 描述 You are given two linked lists representing two non-negative numbers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list. Input: (2 -> 4 -> 3) + (5 -> 6 -> 4)...
* You are given two non-empty linked lists representing two non-negative integers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list. You may assume the two numbers do not contain any leading zero,...
You may assume the two numbers do not contain any leading zero, except the number 0 itself. Example 1: Input: l1 = [2,4,3], l2 = [5,6,4] Output: [7,0,8] Explanation: 342 + 465 = 807. Example 2: Input: l1 = [0], l2 = [0] ...
add-two-numbers-ii 注意:有一种好的方法,是将链表倒转,然后依次相加。 但是,按照题目要求,用了不改变原链表的方法。 就是将两个链表增加到相同长度,然后递归相加,子函数返回后处理进位。 package com.company; import java.util.*; class ListNode {
1. Take two numbers as input. 2. Find the sum of two numbers using function and “+” operator. 3. Print the final result and exit. Addition of Two Numbers in C can be found out in following ways: advertisement Addition of Two Numbers in C using Naive Approach ...
Runtime: 24 ms, faster than 91.59% of C++ online submissions for Add Two Numbers. 好的 这个faster than 91.59%引起极度舒适23333 Fastest Solution(16ms) 然后再来看看大神的解法: staticconstautoio_sync_off=[](){std::cin.tie(nullptr);std::ios::sync_with_stdio(false);std::cout.tie(nullptr...