Add the two numbers and return it as a linked list. You may assume the two numbers do not contain any leading zero, except the number 0 itself. 翻译 给定两个非空的链表,代表两个非负整数。这两个整数都是倒叙存储,要求返回一个链表,表示这两个整数的和。 样例 Input: (2 -> 4 -> 3) +...
classSolution(object):defaddTwoNumbers(self,l1,l2):""":type l1: ListNode:type l2: ListNode:rtype: ListNode"""carry=0cur=dummy=ListNode(0)#遍历l1, l2 链表,并依次赋值给cur 节点whilel1orl2:ifl1andl2:ifl1.val+l2.val+carry>=10:cur.next=ListNode((l1.val+l2.val+carry)%10)carry=1els...
由于这边的l1跟l2的长度可能不一样,所以说我们处理的时候呢就是说必须得遍历到它们俩都不为空为止,所以的话我们这里推荐一个用一个大的while循环,就是这里 classSolution {public://carry(进位),长度不一ListNode* addTwoNumbers(ListNode* l1, ListNode*l2) { ListNode* head =newListNode(-1);//哨兵//ListN...
LeetCode 2. Add Two Numbers You are given two non-empty linked lists representing two non-negative integers. The digits are stored in reverse order, and each of their nodes contains a single digit. Add the two numbers and return the sum as a linked list. You may assume the two numbers ...
工具/原料 Leetcode c++ 方法/步骤 1 问题描述：您将获得两个非空链表，表示两个非负整数。 数字以相反的顺序存储，每个节点包含一个数字。 添加两个数字并将其作为链接列表返回。您可以假设这两个数字不包含任何前导零，除了数字0本身。2 问题示例：输入：（2 - > 4 - > 3）+（5 - > 6 - > 4）...
leetcode Add Two Numbers 解决思路 /* * You are given two non-empty linked lists representing two non-negative integers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list....
add_two_numbers_1( l1: Option<Box<ListNode>>, l2: Option<Box<ListNode>>, ) -> Option<Box<ListNode>> { let mut dump_head = ListNode::new(0); let mut current = &mut dump_head; let mut carry = 0; let mut p = l1.as_ref(...
publicclassSolution{publicListNodeaddTwoNumbers(ListNodel1,ListNodel2){ListNodep1=l1;ListNodep2=l2;ListNodehead=newListNode(0);ListNodep=head;intcarry=0;intsum=0;intlocal=0;while(p1!=null&&p2!=null){sum=p1.val+p2.val+carry;local=sum%10;p.next=newListNode(local);p=p.next;carry=sum/10;...
https://leetcode.com/problems/add-two-numbers/ You are given two linked lists representing two non-negative numbers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list. ...
addTwoNumbers(l1, l2); 72 while (l != NULL){ 73 cout << l->val << endl; 74 l = l->next; 75 } 76 while (1); 77 } 运行结果: 最后实现不等长有进位的求和,即实现题目要求(注意最后一位有进位的情况) 代码语言:javascript 复制 1 #include <iostream> 2 3 using namespace std; 4 ...