leetcode - 2. Add Two Numbers Degree Medium ★★★ε=(´ο`*))) Description You are given two non-empty linked lists representing two non-negative integers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a...
第四章 LeetCode 题解 0001~0099 0001. Two Sum 0002. Add Two Numbers 0003. Longest Substring Without Repeating Characters 0004. Median of Two Sorted Arrays 0005. Longest Palindromic Substring 0006. Zig Zag Conversion 0007. Reverse Integer 0008. String to Integer Atoi 0009. Palindrome Number 0011...
网上的代码:https://discuss.leetcode.com/topic/65279/easy-o-n-java-solution-using-stack,最后几步指针没有看懂,使用stack也就是为了先计算靠右的数字,没有看懂的部分可可以用字符串来实现
You are given two linked lists representing two non-negative numbers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list. Input:(2 -> 4 -> 3) + (5 -> 6 -> 4) Output:7 -> 0 -> 8 考查...
0004-median-of-two-sorted-arrays.py 0005-longest-palindromic-substring.py 0007-reverse-integer.py 0010-regular-expression-matching.py 0011-container-with-most-water.py 0012-integer-to-roman.py 0013-roman-to-integer.py 0014-longest-common-prefix.py 0015-3sum.py 0017-lette...
LeetCode之Add Digits 1、题目 Given a non-negative integer num, repeatedly add all its digits until the result has only one digit. For example: Given num = 38, the process is like: 3 + 8 = 11, 1 + 1 = 2. Since 2 has only one digit, return it....
/// Source : https://leetcode.com/problems/add-to-array-form-of-integer/ /// Author : liuyubobobo /// Time : 2019-02-13 #include <iostream> #include <vector> using namespace std; /// Array and number addition /// Time Complexity: O(n) /// Space Complexity: O(...
package leetcode func minAddToMakeValid(S string) int { if len(S) == 0 { return 0 } stack := make([]rune, 0) for _, v := range S { if v == '(' { stack = append(stack, v) } else if (v == ')') && len(stack) > 0 && stack[len(stack)-1] == '(' { sta...
classSolution(object): def addTwoNumbers(self, l1, l2): l3= ListNode(0) current=l3 carry=0whilel1 or l2: #1,1| None,1|1,None # Pad0ifNoneifl1isNone: l1v=0else: l1v=l1.valifl2isNone: l2v=0else: l2v=l2.val # Sum
leetcode Add Two Numbers(对指针的一些基本操作) 1ListNode *ptr,*l;2l =newListNode(0);//这才是正确的赋值姿势3ptr = l;//赋给的是地址4intup =0,fg1 =0,fg2 =0;5//cout<<"r"<<endl;6while(1)7{8if(fg1 && fg2)break;9inta,b;10if(fg1) a =0;11elsea = l1 ->val;12if(fg2...