思路:将A中每次从后往前取的数,加到K上面(K最大为10000,不存在越界问题),然后每次取K的最后一位数(借助取余),计算完后将K除以10,直到K等于0。 publicList<Integer>addToArrayForm2(int[] A,intK){ List<Integer> result =newArrayList<Integer>();inti=A.length-1, tem = K;while(i >=0|| tem >...
leetcode 989. 数组形式的整数加法(Add to Array-Form of Integer) 目录 题目描述: 示例1: 示例2: 示例3: 示例4: 解法: 题目描述: 对于非负整数 X 而言,X 的数组形式是每位数字按从左到右的顺序形成的数组。例如,如果 X = 1231,那么其数组形式为 [1,2,3,1]。 给定非负整数 X 的数组形式 A,返回...
For a non-negative integer X, the array-form of X is an array of its digits in left to right order. For example, if X = 1231, then the array form is [1,2,3,1]. Given the array-form A o...
1. 989. Add to Array-Form of Integer; 2. cplusplus_std::reverse; 完
vector<int> addToArrayForm(vector<int>& A, int K) {vector<int> result;for (int i = A.size() - 1; i >= 0; i --) {int num = A[i];K += num; //得到末位和int remind = K % 10;result.insert(result.begin(), remind);K /= 10;}if (K) {while (K > 9) { //如果K...
0989 Add to Array-Form of Integer Go 45.5% Easy 0990 Satisfiability of Equality Equations Go 50.7% Medium 0991 Broken Calculator Go 54.1% Medium 0992 Subarrays with K Different Integers Go 54.3% Hard 0993 Cousins in Binary Tree Go 54.1% Easy 0994 Rotting Oranges 52.4% Medium 0995 ...
【题目】Given an integer array nums, find the sum of the elements between indices i and j (i ≤ j), inclusive. The update(i, val) function modifies nums by updating the element at index i to val. Example: 代码语言:javascript 代码运行次数:0 运行 复制 Gi...
【题目】Given a non-empty array containing only positive integers, find if the array can be partitioned into two subsets such that the sum of elements in both subsets is equal. Note: Each of the array element will not exceed 100. The array size will not exceed 200. Example 1: ...
989 Add to Array-Form of Integer Easy Solution 990 Satisfiability of Equality Equations Medium Solution 991 Broken Calculator Medium Solution 992 Subarrays with K Different Integers Hard Solution 993 Cousins in Binary Tree Easy Solution 994 Rotting Oranges Medium Solution 995 Minimum Number of K Conse...
326. Power of ThreeGiven an integer, write a function to determine if it is a power of three.(判断一个数是否是3的次方数,不使用循环和迭代)由于输入是int,正数范围是0-231,在此范围中允许的最大的3的次方数为319=1162261467,那么我们只要看这个数能否被n整除即可。class...