classSolution{public:// 大整数加法stringaddStrings(stringnum1,stringnum2){stringn1(num1.rbegin(), num1.rend());stringn2(num2.rbegin(), num2.rend());intsize1 = n1.length();intsize2 = n2.length();if(size1 < size2) {for(inti =0; i < size2 - size1; i++) { n1 +='0';...
publicclassSolution {publicString addStrings(String num1, String num2) {if(num1 ==null|| num2 ==null) {returnnull; }intsum = 0; StringBuilder str=newStringBuilder();for(inti = num1.length() - 1, j = num2.length() - 1; i >= 0 || j >= 0; i--, j--) {intx = i <...
Can you solve this real interview question? Add Strings - Given two non-negative integers, num1 and num2 represented as string, return the sum of num1 and num2 as a string. You must solve the problem without using any built-in library for handling large
AI检测代码解析 class Solution { public String addStrings(String num1, String num2) { StringBuilder res = new StringBuilder(); // 返回结果 int p1 = num1.length() - 1; // 标记遍历到 num1 的位置 int p2 = num2.length() - 1; // 标记遍历到 num2 的位置 int carry = 0; // 进位 ...
add-strings https://leetcode.com/problems/add-strings/ package com.company; import java.util.LinkedList; import java.util.List; import java.util.Random; public class Main { public String addStrings(String num1, String num2) { StringBuilder sb = new StringBuilder();...
sample["generation"] = sample["canonical_solution"] sample["test_code"] = process_humaneval_test(sample, problems, example_test, language) if sample["test_code"] is None: continue args = (task_id, sample, lang, timeout, tmp_dir_, completion_id[task_id]) future = executor.submit(chec...
Evaluation/LeetCode/human_eval/data.py +49 Original file line numberDiff line numberDiff line change @@ -0,0 +1,49 @@ 1 + from typing import Iterable, Dict 2 + import gzip 3 + import json 4 + import os 5 + 6 + 7 + ROOT = os.path.dirname(os.path.abspath(__fi...
【Leetcode】Add Strings Given two non-negative integers num1 and num2 represented as string, return the sum of num1 and num2. 1 注意题中num1和num2是以string形式储存的,所以在做运算的时候需要转换成ASCII,用ord()函数 2 题中num1和num2以string形式存储,若不能用build-in函数,则需要先把string...
Leetcode 67 Add Binary 编程算法 Given two binary strings, return their sum (also a binary string). For example, a = "11" b = "1" Return "100". 模拟二进制加法,先逆置字符串,补全短串的前导0,最后注意首位进位! class Solution { public: string addBinary(string a, string b) { reverse(...
//add stringclass Solution{public:stringaddStrings(string num1,string num2){string ans;inti=num1.size()-1;intj=num2.size()-1;intcarry=0;while(i>=0||j>=0||carry){intsum=0;if(i>=0){sum+=num1[i]-'0';i--;}if(j>=0){sum+=num2[j]-'0';j--;}sum+=carry;carry=sum/10...