classSolution{public:// 大整数加法stringaddStrings(stringnum1,stringnum2){stringn1(num1.rbegin(), num1.rend());stringn2(num2.rbegin(), num2.rend());intsize1 = n1.length();intsize2 = n2.length();if(size1 < size2) {for(inti =0; i < size2 - size1; i++) { n1 +='0';...
classSolution {public:stringaddStrings(stringnum1,stringnum2) {strings;intcarry =0;inti = num1.size() -1;intj = num2.size() -1;while(i >=0|| j >=0||carry) {intsum =0;if(i >=0) { sum= sum + num1[i] -'0'; i--; }if(j >=0) { sum= sum + num2[j] -'0'; ...
Java 语言代码如下: class Solution { public String addStrings(String num1, String num2) { StringBuilder res = new StringBuilder(); // 返回结果 int p1 = num1.length() - 1; // 标记遍历到 num1 的位置 int p2 = num2.length() - 1; // 标记遍历到 num2 的位置 int carry = 0; // ...
leetcode 415 字符串相加 add-strings【ct】 415. 字符串相加 难度简单 724 给定两个字符串形式的非负整数num1和num2,计算它们的和并同样以字符串形式返回。 你不能使用任何內建的用于处理大整数的库(比如BigInteger), 也不能直接将输入的字符串转换为整数形式。 示例1: 输入:num1 = "11", num2 = "123...
0271-encode-and-decode-strings.py 0286-walls-and-gates.py 0287-find-the-duplicate-number.py 0290-word-pattern.py 0295-find-median-from-data-stream.py 0297-serialize-and-deserialize-binary-tree.py 0300-longest-increasing-subsequence.py 0309-best-time-to-buy-and-sell-sto...
sample["generation"] = sample["canonical_solution"] sample["test_code"] = process_humaneval_test(sample, problems, example_test, language) if sample["test_code"] is None: continue args = (task_id, sample, lang, timeout, tmp_dir_, completion_id[task_id]) future = executor.submit(chec...
【Leetcode】Add Strings Given two non-negative integers num1 and num2 represented as string, return the sum of num1 and num2. 1 注意题中num1和num2是以string形式储存的,所以在做运算的时候需要转换成ASCII,用ord()函数 2 题中num1和num2以string形式存储,若不能用build-in函数,则需要先把string...
Leetcode 67 Add Binary 编程算法 Given two binary strings, return their sum (also a binary string). For example, a = "11" b = "1" Return "100". 模拟二进制加法,先逆置字符串,补全短串的前导0,最后注意首位进位! class Solution { public: string addBinary(string a, string b) { reverse(...
//add stringclass Solution{public:stringaddStrings(string num1,string num2){string ans;inti=num1.size()-1;intj=num2.size()-1;intcarry=0;while(i>=0||j>=0||carry){intsum=0;if(i>=0){sum+=num1[i]-'0';i--;}if(j>=0){sum+=num2[j]-'0';j--;}sum+=carry;carry=sum/10...
[LeetCode]--67. Add Binary Given two binary strings, return their sum (also a binary string). For example, a = “11” b = “1” Return “100”. 二进制算法,加上对字符串的处理。 看了一下专业人士写的,跟我差不太多,还是有一点可以借鉴。如果没必要保持原......