正常情况:此解法是利用迭代,使用两层循环,外层判断大小,内层进行数据计算,先对10取余,再除以10,进入下一位接着计算,如果算到最后一位,跳出内层循环,此时还要加上对10取余的余数,因为内层循环只是做判断,然后将算出的和赋值给num,sum归为0,再开始下一次的循环。 publicintaddDigits2(intnum) {if(num<10) {...
publicclassSolution { publicintaddDigits(intnum) { return(num -1) %9+1; } }
Given a non-negative integer num, repeatedly add all its digits until the result has only one digit. For example: Given num = 38, the process is like: 3 + 8 = 11, 1 + 1 = 2. Since 2 has only one digit, return it. 题意:给一个非负整数,求其各位数的和只至最后是个位数。 1 ...
// For user input // Use Scanner or BufferedReader // Two objects of String // Holds the values to sum // The number's length is of 400 digits // Which is out of range of double String input1 = "012345678901234567" + "8901234567890123" + "4567890123456789" + "0123456789012345" + "...
running on Java 1.4, of course, you will cry for the update to at least Java 1.5 until you are tired of asking it. No need to be disappointed, Java 1.4 hasDecimalFormatto help you out. The following code willadd leading zeros to the input numberif a number has less than 4 digits. ...
You are given two non-empty linked lists representing two non-negative integers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list. ...
For all other decimal functionality we have placed them in_decimal.yamlfiles. Not sure if we want to have just this one function in a file by itself though. extensions/functions_rounding.yamlOutdated When `s` is a negative number, the rounding is ...
negative integers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list. You may assume the two numbers do not contain any leading zero, except the number 0 itself. https://leetcode.com/problems/two-...
You are given two non-empty linked lists representing two non-negative integers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list. You may assume the two numbers do not contain any leading zero, exc...
* @exception IllegalArgumentException if min>max or if numbers in the interval cannot be expressed * with the given fixed number of digits */publicstaticAutomatonmakeInterval(intmin,intmax,intdigits)throwsIllegalArgumentException{Automatona=newAutomaton();Stringx=Integer.toString(min);Stringy=Integer....