正常情况:此解法是利用迭代,使用两层循环,外层判断大小,内层进行数据计算,先对10取余,再除以10,进入下一位接着计算,如果算到最后一位,跳出内层循环,此时还要加上对10取余的余数,因为内层循环只是做判断,然后将算出的和赋值给num,sum归为0,再开始下一次的循环。 publicintaddDigits2(intnum) {if(num<10) {...
258. Add Digits Java Solutin Given a non-negative integernum, repeatedly add all its digits until the result has only one digit. For example: Givennum = 38, the process is like:3 + 8 = 11,1 + 1 = 2. Since2has only one digit, return it. Follow up: Could you do it without an...
Given a non-negative integer num, repeatedly add all its digits until the result has only one digit. For example: Given num = 38, the process is like: 3 + 8 = 11, 1 + 1 = 2. Since 2 has only one digit, return it. 题意:给一个非负整数,求其各位数的和只至最后是个位数。 1 ...
题目链接:https://leetcode.com/problems/add-digits/ 题目: num, repeatedly add all its digits until the result has only one digit. For example: num = 38, the process is like:3 + 8 = 11,1 + 1 = 2. Since2 Follow up: Could you do it without any loop/recursion in O(1) runtime?
LeetCode 258 Add Digits(数字相加,数字根) 翻译 给定一个非负整型数字,反复相加其全部的数字直到最后的结果仅仅有一位数。 比如: 给定sum = 38,这个过程就像是:3 + 8 = 11。1 + 1 = 2。由于2仅仅有一位数。所以返回它。 紧接着: 你能够不用循环或递归在O(1)时间内完毕它吗?
For all other decimal functionality we have placed them in_decimal.yamlfiles. Not sure if we want to have just this one function in a file by itself though. extensions/functions_rounding.yamlOutdated When `s` is a negative number, the rounding is ...
每日一则 LeetCode: Add Two Numbers 描述 You are given two non-empty linked lists representing two non-negative integers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list....
fieldType - the field type used in the creation of the new field.getFieldPrecisionpublic int getFieldPrecision()Returns the Field Precision parameter of this tool . This parameter is describes the number of digits that can be stored in the field. All digits are counted no matter what side ...
fieldType - the field type used in the creation of the new field.getFieldPrecisionpublic int getFieldPrecision()Returns the Field precision parameter of this tool . This parameter is describes the number of digits that can be stored in the field. All digits are counted ...
Add the sum of its digits to the product of its digits. If the value is equal to the number input, output the message “Special 2-digit number” otherwise; output the message “Not a Special 2-digit number”. 8 + */ 9 + 10 + import java.util.*; 11 + class Special 12 ...