2.德国KENDRION产品分类 德国Kendrion电磁铁、 Kendrion控制器、 Kendrion整流器、 Kendrion离合器、 Kendrion刹车片、 Kendrion电磁振动器3.德国KENDRION电磁铁常用型号 KENDRION电磁铁 GHGX2628.11.00A-03 KENDRION电磁铁 KLMZ-22-Fa 41090 41-90309A00 GOA330AD1 21554-08B1 OLV554001A00 43-111-03D00 D00 ...
如图,△ABC中,AB=AC,∠BAC=90°,BE平分∠ABC交AC于F,CE⊥BF于E,EG⊥AB于G,连AE.下列结论:①AB+AF=BC;②BF=2CE;③FC=GE;④∠GEA=∠CBF.其中正确的有( ) A.1B.2C.3D.4 试题答案 在线课程 分析过F作FK⊥BC于K,根据等腰直角三角形的性质得到∠ABC=∠ACB=45°,由等腰直角三角形性质得到CK=FK...
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3.如图,△ABC是边长为2√3的等边三角形,已知G是边AB上的一个动点(G点不与A,B点重合),且GE∥AC,GF∥BC,若AG=x,S △GEF =y.
(1)△ABC是等腰三角形;(2)BF=AC;(3)BH:BD:BC=1: : ;(4)GE2+CE2=BG2. A.1个B.2个C.3个D.4个 【答案】C 【解析】 (1)根据角平分线的定义可得∠ABE=∠CBE,根据等角的余角相等求出∠A=∠BCA,再根据等角对等边可得AB=BC,从而得证; ...
-x_2)\cdots(x_{n-1}-x_{n-2})\\ &\cdots(x_2-x_1)\\ &\color{grey}{1.盯着第二行\quad2.大的减小的\\} \end{aligned} \begin{aligned} \ [例1]&\color{maroon}{\begin{vmatrix}b+c&c+a&a+b\\a&b&c\\a^2&b^2&c^2 \end{vmatrix}}\\ =&\begin{vmatrix}a+b+c&a+b+...
2. The history of TCM formulas in the treatment of cancer 3. Mechanisms of TCM formulas in preventing and treating cancer 4. Clinical applications of TCM formulas 5. Conclusions and perspectives Funding Declaration of Competing Interest ReferencesShow full outline Cited by (79) Figures (4) Table...
∴GF=HE 同理可得 GE =HF. ∴以E、F、G、H为顶点的四边形是平行四边形. (2)连结 GH,∵∠B=90°,AB =6 cm,BC=8 cm, ∴AC=√(AB^2+BC^2)=√(6^2+8^2)=10cm. ∵BG∥CH,且由(1)易得 BG=CH, ∴四边形BCHG是平行四边形, ∴. GH=BC=8 cm,当 EF=GF=8 cm 时,以E、G、...
故CE=GE,CG=2CE,又△ABC为等腰直角三角形，故AB=AC，ASA可证Rt△ABD≌Rt△ACG，BD=CG=2CE。
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