How do you solve 2x + 3y = 6 and x + 2y = 5?Elimination Method:Multiply both sides of the equation by the suitable number to make the coefficient of any one variable same in both equations, then subtract one equation from other equation that eliminate one variable and solve that ...
We need to find the point on the line2x+3y=6that is closest to the origin(0,0). The shortest distance from a point to a line is along the perpendicular from the point to the line. Step 2: Find the slope of the line The equation of the line can be rewritten in slope-intercept ...
Solving Equation:In order to solve an equation, we need to know the different characteristics of the given equation. On the other hand, we also need to follow the rules associated to the type of equation given.Answer and Explanation: We are given the equation {eq}2x - 3y = 6 {/eq}. ...
2x−3y=12,x+3y=6. View Solution The equation of the tangent to the curve y=2.e−x3 where it crosses the y- axis is (A)2x+3y=0 (B)2x+3y=9 (c)2x+3y=4 (D)2x+3y=6 View Solution (6) 2x−3y=4; 3y−x=4 View Solution 2x−[3y−{2x−(y−x)}]=? View ...
Answer to: Write the equation 2x - 3y = 6 in slope-intercept form. By signing up, you'll get thousands of step-by-step solutions to your homework...
10 The plane p has equation 2x -3y+ 6z= 16. The plane q is parallel to p and contains the point with position vector i +4j+2k.(i) Find the equation of q, giving your answer in the form ax + by +cz = d.[2](ii) Calculate the perpendicular distance between p and q.[3] ...
代数输入 三角输入 微积分输入 矩阵输入 2x+y+z=3 求解x 的值 x=23−z−y 求解y 的值 y=3−z−2x 测验 Linear Equation 2x+y+z=3
24 The equation of a straight line is 3y + 2x + 6 =0.Find(a) the gradient of the line,Answer[1](b) the coordinates of the point where the line intersects the y-axis,(0,-2)Answer (...,...) [1](c) the coordinates of the point at which the line intersects the line y=...
1) 2x-3y = 6 If a st. line passes through the point line on the co-ordinate axes, then the equation of the line is 3x + 2y-1 0 2) 2x+3y-2 0 2)2x+3y-6=0 3) 2x
To reduce the equation 2x−3y−6z=14 to normal form and find the length of the perpendicular from the origin to the plane, as well as the direction cosines of the normal to the plane, follow these steps: Step 1: Write the given equationThe given equation of the plane is:2x−3y...