Verify the identity. \cot(x - \pi/2) = -\tan x Verify the following identity: csc^2(x)\: sec(x) = sec(x) + csc(x) \: cot(x). Verify the identity. sinx/1-sinx - cosx/1-cosx = 1-cotx/cscx-1 Prove if an identity \csc(x) - \cot(x) = \frac{\sin(x)}{1 + \co...
Evaluate: int(-pi//2)^(pi//2)1/(1+e^(sin x))dx 05:57 The value of int-pi^pi cos^2x/[1+a^x]dx, a > 0 is 11:45 Free Ncert Solutions English Medium NCERT Solutions NCERT Solutions for Class 12 English Medium NCERT Solutions for Class 11 English Medium ...
We can use the identity cosx=1−2sin2(x2) to rewrite the equation:2sinx+(1−2sin2(x2))=1This simplifies to:2sinx+1−2sin2(x2)=1Thus,2sinx=2sin2(x2) Step 5: Solve for sinxUsing the double angle formula sinx=2sin(x2)cos(x2):2(2sin(x2)cos(x2)=2sin2(x2)...
Calculus Inputs Matrix Inputs cos(?)−12!(cos(?)x+sin(?)x cos−12(cosx+sinx Evaluate arccos(22(sin(x)+cos(x))) Differentiate w.r.t. x −−sin(2x)+1cos(x)−sin(x) Graph
Using the Pythagorean identity sin2x+cos2x=1:1+6+tan2x+cot2x=7+tan2x+cot2x Step 3: Set the equation equal to the right-hand sideNow we have:7+tan2x+cot2x=k+tan2x+cot2x Step 4: Solve for kBy comparing both sides, we can see that:k=7 ConclusionThus, the value of k is 7....
Using the identity s=sinx+cosx and knowing that s can be expressed as √2+2cos(2x), we can find sin2x in terms of a and b:sin2x=a−b√2 Step 7: Compare and find a and bFrom our earlier calculations, we can find the values of a and b by comparing the coefficients. After ...
∫π/20sinxsinx+cosxdx View Solution IfA=∫π0sinxsinx+cosxdxandB=∫π0sinxsinx−cosxdx, then View Solution IfA=∫π0sinxsinx+cosxdx,B=∫π0sinxsinx−cosxdx, then View Solution Free Ncert Solutions English Medium NCERT Solutions
To solve the expression (sinx+cscx)2+(cosx−secx)2−(tanx+cotx)2, we can follow these steps: Step 1: Expand the squaresUsing the algebraic identity (a+b)2=a2+b2+2ab and (a−b)2=a2+b2−2ab, we can expand each term. 1. Expand (sinx+cscx)2: (sinx+cscx)2=sin2x+csc2x...
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