=1/根号下(x^2+1)您好，z = ln√（x²+y²）= (1/2) ln( x²+y² )δz/δx = (1/2) * 1/( x²+y² ) * 2x = x /( x²+y² )δz/δy = (1/2) * 1/( x²+y² ) * 2y = y/( x²+y²)
答案解析 查看更多优质解析 解答一 举报 z=ln根号下(x的平方+y的平方)z对x的偏导数=[根号下(x^2+y^2)]'/根号下(x^2+y^2)=2x/2(x^2+y^2)=x/(x^2+y^2)同理z对y的偏导数=y/(x^2+y^2) 解析看不懂?免费查看同类题视频解析查看解答 ...