map<String,Object> map1 = new HashMap<>(); map1.put("a_id",1); map1.put("in_num",10); map<String,Object> map2 = new HashMap<>(); map1.put("a_id",3); map1.put("in_num",10); map<String,Object> map3 = new HashMap<>(); map1.put("a_id",4); map1.put("in...
/***@paramm1*@paramm2*@paramstring 根据某个key来合并*@return*/publicstaticList<Map<String,Object>> merge(List<Map<String,Object>> m1,List<Map<String,Object>>m2,String string){m1.addAll(m2);Set<String> set =newHashSet<>();returnm1.stream().collect(Collectors.groupingBy(o ->{//暂存...
val map1 = mutable.Map("a"->1, "b"->2, "c"->3) val map2 = mutable.Map("a"->4, "b"->5, "d"->6) val map3: mutable.Map[String, Int] = map2.foldLeft(map1) { (map, kv) => { val k = kv._1 val v = kv._2 map(k) = map.getOrElse(k, 0) + v map } ...
得到List<HashTable>里面的list然后取list的某一项 2019-12-04 15:19 − //得到List<HashTable>里面的listUnFix然后取listUnFix判断tempfix里面得值 List<Hashtable> list = new List<Hashtable>(); for (int... 枫岫 0 785 java之List<Object>转List<Map<String, Object>> 2019-12-09 11:19 ...
很简单，换个思路，先把两个list转成json数组合并，再转成list.json和list互转网上好多工具类
给你一个参考的代码：HashMap listMap1 = new HashMap();for (int i = 0; i < 3; i++) { MyClass class1=new MyClass();class1.setClassID(i+1);class1.setClassName("班级"+(i+1));ArrayList list = new ArrayList();int count=(int) (Math.random() * 7)+1;for (int ...
就是当比较两个String对象内容是否相等时，我第一次使用==没有得到预想到的结果，改成String的equals(...
以下是一个通过使用HashMap来找出两个List中的重复元素的代码示例。 import java.util.*; public class Main { public static void main(String[] args) { List<Integer> list1 = Arrays.asList(1, 2, 3, 4, 5); List<Integer> list2 = Arrays.asList(4, 5, 6, 7, 8); ...
两个for循环，把list1里的属性与list2的每个属性进行比较
String zheng= zhengMap.get("0").toString(); String fan= fanMap.get("0").toString();if(zheng.equals(fan) && fanMap.get("4") ==null){for(Map.Entry<String,Object>entry:zhengMap.entrySet()){if(!entry.getKey().equals("0")){doublevalue1 =CastUtil.castDouble(fanMap.get(entry.get...