要将List<Map<String, Object>>中所有map的key对应的值合并为字符串,你可以按照以下步骤进行操作: 创建一个空的字符串用于存储结果:这将用于累积所有key对应的值。 使用流遍历list中的每个map:通过Java 8的流操作,可以方便地遍历集合。 对于每个map,遍历其中的键值对,取出key对应的值:这里可以使用...
String num= map.get("num").toString(); //if识别到部门后,会将num赋值到count中,否则会将没识别到的部门存放到新建的newList中 count+=Integer.valueOf(num); }else{ newList.add(map); } } //在新建一个Map存储要替换合并数据,在添加到newList中 Map<String,Object> map =newLinkedHashMap<>();...
List<Map<String, Object>> resultList = m1.stream().collect(Collectors.groupingBy(o ->{//暂存所有keyset.addAll(o.keySet());returno.get(key); })).entrySet().stream().map(o->{//合并Map<String, Object> map = o.getValue().stream().flatMap(m ->{returnm.entrySet().stream(); })...
Map<String,Object> h1 = new HashMap<>(); h1.put("12","fdsa"); h1.put("123","fdsa"); h1.put("124","fdsa"); h1.put("125","fdsa"); Map<String,Object> h2 = new HashMap<>(); h2.put("h12","fdsa"); h2.put("h123","fdsa"); h2.put("h124","fdsa"); h2.put("...
Map<String, Object> map2 = new HashMap<>(); map2.put("key3", value3); map2.put("key4", value4); list2.add(map2); 代码语言:txt 复制使用流连接两个列表。可以使用Stream类的concat方法将两个列表合并为一个流,然后进行后续操作。例如:Stream<Map<String, Object>> combinedStream = ...
Map<String,Object> h1 = new HashMap<>(); h1.put("12","fdsa"); h1.put("123","fdsa"); h1.put("124","fdsa"); h1.put("125","fdsa"); Map<String,Object> h2 = new HashMap<>(); h2.put("h12","fdsa"); h2.put("h123","fdsa"); h2.put("h124","fdsa"); h2.put(...
Map<String,Object> h1 = new HashMap<>(); h1.put("12","fdsa"); h1.put("123","fdsa"); h1.put("124","fdsa"); h1.put("125","fdsa"); Map<String,Object> h2 = new HashMap<>(); h2.put("h12","fdsa"); h2.put("h123","fdsa"); h2.put("h124","fdsa"); h2.put(...
* @Description: 合并两个list<map>,并将userId相同的其它属性合并 * @Title: mergeList * @param: @return * @return: List<Map<String,Object>> * @throws */publicstaticList<Map<String,Object>>mergeList(){//构建List集合1List<Map<String,Object>>list1=newArrayList<>();Map<String,Object>data=...
class Test2 {public static void main(String[] args) {Map<String, String> map1 = new MyMap<>();map1.put("name", "张三");map1.put("公司", "腾讯");Map<String, String> map2 = new MyMap<>();map2.put("name", "李四");map2.put("公司", "阿里");Map<String,...
//合并 Map<String, Object> map = o.getValue().stream().flatMap(m->{ return m.entrySet().stream(); }).collect(Collectors.toMap(Map.Entry::getKey, Map.Entry::getValue, (a,b)->b)); //为没有的key赋值0 set.stream().forEach(k->{ ...