Evaluate:∫sin(x−a)sinxdx View Solution Evaluate: (i)∫sin(x−a)sin(x−b)dx(ii)∫sin(x−α)sin(x+α)dx View Solution Evaluate: (i)∫sin(x−a)sin(x−b)dx(ii)∫sin(x−α)sin(x+α)dx View Solution Evaluate:∫sin(x−α)sin(x+α)dx ...
Evaluate: underset(0)overset(pi//2)int(x)/(sinx+cosx)dx 07:47 For the following (1-4) different results,Write the corresponding inte... 01:37 For the following (1-4) different results,Write the corresponding inte... 01:33 For the following (1-4) different results,Write the correspon...
此题可利用万能公式代换将三角函数化为有理函数进行积分:设u=tan(x/2)则du=d(tanx/2)=(1/2)(secx/2)^2dx=(1/2)(1+u^2)dx,则dx=2du/(1+u^2)sinx=2u/(1+u^2)所以:∫1/(1+sinx)dx =∫2du/(1+u^2)[1+2u/(1+u^2)]=∫2du/(1+u^2+2u)=∫2d(1+u)/(1+u)^2=...
\int x \sin 3x^2dx \ 2. \int \frac{\sec^2 x}{\sqrt{\tan xdx Evaluate the integral using substitution Indefinite integral of cos^4x sinx dx. Evaluate the following indefinite \int ((\frac {7}{\sqrt x})+7\sqrt x)dx Evaluate the indefinite integral. \int 9x^2 \sin...
用万能代换∫1/(1+sinx)dx=∫[sin^2(x/2)+cos^2(x/2)]/[sin^2(x/2)+cos^2(x/2)+2sin(x/2)cos(x/2)]dx=∫[1+tan^2(x/2)]/[tan^2(x/2)+1+2tan(x/2)]dx=∫sec^2(x/2)/[tan(x/2)+1]^2dx=2∫1/[tan(x/2)+1]^2dtan(x/2)=-2/[tan(x/2)+1]+C相关...
NCERT solutions for CBSE and other state boards is a key requirement for students. Doubtnut helps with homework, doubts and solutions to all the questions. It has helped students get under AIR 100 in NEET & IIT JEE. Get PDF and video solutions of IIT-JEE Mains & Advanced previous year pap...
NCERT solutions for CBSE and other state boards is a key requirement for students. Doubtnut helps with homework, doubts and solutions to all the questions. It has helped students get under AIR 100 in NEET & IIT JEE. Get PDF and video solutions of IIT-JEE Mains & Advanced previous year pap...