∫x2+1(2x+1)(x2−1dx : ∫3x−2(x+12(x+3dx निम्नलिखित समाकलों का मान ज्ञात कीजिए ∫dx निम्नलिखित समाकलों का मान ज्ञा...
Answer Step by step video, text & image solution for int_(-pi)^(pi)(2x(1+sinx))/(1+cos^(2)x)dx का मान ज्ञात कीजिए। by Maths experts to help you in doubts & scoring excellent marks in Class 12 exams. Updated on:21/07/2023 नि...
解析 解:令t=aecsinx则dt=\dfrac{1}{\sqrt{1-x62}} ,x=sint则原式=\int {(sint\cdot t)}\,{\rm dt}=\dfrac{v=t,dv=sintdt}{dv=dt,v=-cost} -tcost+\int{cost}\,{\rm dt}=-t\cdot cost+sint+C=-arcsinx(1-x^2)+x+C...
求不定积分∫(ln3x-2sinx)dx ∫(ln3x-2sinx)dx >> syms x yy=log(3*x)-2*sin(x);int(y)ans =2*cos(x) - x + x*log(3*x)定积分∫_0^1(x^2+1)arccosxd ∫_0^1(x^2+1)arccosxd >> syms x yy=(x^2+1)*acos( ) ...
(1)∫_1^22xdx=2∫_1^2xdx=2x1/2x^2l^2=1-1=1,综上,结论是:4(2)∫_(-π)^πsinxdx=-cosx|^n=-cosπ-cos(-π)=0综上,结论是:O(3)设y=√(4-x^2),0≤x≤2,0≤y≤2,平方可得x^2+y^2=4且0≤x≤2,0≤y≤2,即∫_1^2√(1-x^2)dx表示四分之一圆的面...
8.以下四个命题中.正确命题的个数是( )①命题“若x=y.则sinx=siny 的逆否命题是真命题,②已知α.β是不同的平面.m.n是不同的直线.m∥α.n∥β.α⊥β.则m⊥n,③直线l1:2ax+y+1=0.l2:x+2ay+2=0.l1∥l2的充要条件是$a=\frac{1}{2}$,④$\int {-1}^1{sinxdx=0}$.A.1B.2C.3D
解答解:对于A,∫π−π∫−ππsinxdx=-cosx|π−π−ππ=-(1-1)=0,故A正确, 对于B,∫π2−π2∫−π2π2cos2xdx=1212sin2x|π2−π2−π2π2=1212(0-0)=0,故B不正确, 对于C,因为y=cosx为偶函数,故C正确, 对于D,∫10∫01√xxdx=2323x32x32|1001=2323,故D正确, ...
百度试题 结果1 题目lim_(x→0)sinxcos(1,costsinx/2sin2xdxsintlnsintxsintlnxsinxcosθ=0.1 相关知识点: 试题来源: 解析 What:usedfor 反馈 收藏
Answer to: Evaluate the integral of \int\limits_{-1}^1 (\frac{sinx}{1+x^2})dx By signing up, you'll get thousands of step-by-step solutions to your...
解答解:∫50∫05(2x-4)dx=(x2-4x)|5005=25-20=5, ∫π0∫0πcosxdx=sinx|π00π=0, ∫31∫131x1xdx=lnx|3113=ln3, ∫π0∫0πsinxdx=-cosx|π00π=-(-1-1)=2, 故选:D 点评本题考查了定积分的计算,关键求出原函数,属于基础题. ...