答:参见本节要点2和4。结点总数n=n+n1+n2+n3+n4,又由于除根结点外,每个结点都对应一个分支,所以总的分支数等于n-1,而度为i(0≤i≤4)的结点的分支数为i,所以有:n-1=0×n+1×n1+2×n2+3×n3+4×n4。综合两式得:n=n2+2n3+3n4+1=3+2×2+3×2=14。n=n+n1+n2+n3+n4=14+4+3+2...
答:参见本节要点2和4。结点总数n=n+n1+n2+n3+n4,又由于除根结点外,每个结点都对应一个分支,所以总的分支数等于n-1,而度为i(0≤i≤4)的结点的分支数为i,所以有:n-1=0×n+1×n1+2×n2+3×n3+4×n4。综合两式得:n=n2+2n3+3n4+1=3+2×2+3×2=14。n=n+n1+n2+n3+n4=14+4+3+2...