n = int(input("请输入n的值:")) print("{0}的{1}次方为:{2}".format(x, n, power(x, n))) 在该代码中,power(x, n)函数接收两个参数`x`和`n`,并通过循环将`x`连乘`n`次,最后返回结果。主函数中,先要分别输入`x`和`n`的值,然后调用`power(x, n)`函数,将返回结果打印出来。请注...
解析 #include<stdio.h>double power(double x, int n){ double p=1.0; while(n>0) { p=p*x; n--; } return p;}int main(void){ double x; int n; scanf("%lf %d",&x,&n); printf("%lf\n",power(x,n)); return 0;}反馈 收藏 ...
【实验5-2】编写power函数,求x的n次方。编程要求如下:(1)在main函数中,输入x和n,调用power函数,输出计算结果。(2)power函数的原型定义为flo
include<stdio.h>double power(double x, int n){ double p=1.0; while(n>0) { p=p*x; n--; } return p;}int main(void){ double x; int n; scanf("%lf %d",&x,&n); printf("%lf\n",power(x,n)); return 0;} ...
t=(1/x)*rpow(x,n+1);return t;} int main(){ float x,t; int n;printf("请输入x和n")...
void main(){ int x, n;int i;double result=0;pirntf("input x and n:");scnaf("%d %d", &x, &n);result = x;for(i=0; i<n－1; i++){ result *= x;} printf("\nresult is %f\n", result);} 我完全没有调。
include"stdio.h"double fun(double x,int n){ if(n==0) return 1;else return x*fun(x,n-1);}main(){ int n;double x;printf("输入x和n:");scanf("%lf%d",&x,&n);printf("%lf\n",fun(x,n));}
编写X的n次方的递归函数,并在主函数中调用它;有步骤有解释!/// /// The x's power of n /// /// The x /// The n ///
求任意实数的n次幂，参考代码如下:include<stdio.h> double pow_n(double x, int n){ double t=1;int i;if(n>=0){ for(i=1;i<=n;++i)t*=x;}else{ n=-n;for(i=1;i<=n;++i)t*=x;t=1/t;} return t;} int main(){ int n;double y;printf("输入实数Y 整数n\n");...
include<stdio.h>double mypow(double x,int n){if(n==0)return 1; if(n>0)return x*mypow(x,n-1); else return mypow(x,n+1)/x;}int main(){double x; int n; scanf(("%lf%d",&x,&n); printf("%lf\n",mypow(x,n)); return 0;} ...