{ cout<<"ax^3+bx^2+cx+d=0(^为乘方号)在1附近的根为:"; cout< system("pause"); return 0;}double niudun(double a,double b,double c,double d){ double x1,x0=1.0; x1=x0-(a*x0*x0*x0+b*x0*x0+c*x0+d)/(3*a*x0*x0+2*b*x0+c);...