C程序,有一分数序列:2/1 3/2 5/3 8/5 13/8 21/13.求出这个数列的前N项之和,保留两位小数.#include 我不怎么会用数组int main(){\x05float j,nume=2,i,N,d[100]={0,1,2};\x05\x05float s=0;\x05scanf("%f",&N);\x05\x05for(i=1;i 答案 不用数组也行scanf("%f",&...
程序: 1 #include<stdio.h> 2 3 int main() { 4 int i,n; 5 double fz = 1,fm = 0,sum = 2; 6 scanf(&q ... 利用C语言编程:有一个分数序列 2/1+3/2+5/3+8/5+13/8+...,求此序列前N项和的简单解法, #include<stdio.h> #include<stdlib.h> double print_s(int a) { double...
以下的程序求和s=1+1/1!+1/2!+...+1/n!include<stdio.h> int main(){ double e=1,t=1;int i,n;scanf("%d",&n);for(i=1; i<=n; i++){t/=i;e+=t;} printf("%f\n",e);return 0;}
include<stdio.h>void main(){int n;printf("Please enter a integer number :");scanf("%d",&n);int y, c, sum = 0;while((n / 10) != 0){y = n % 10;n = n / 10;sum = sum + y;}printf("result : %d",(sum + n));} ...
利用C语言编程:有一个分数序列 2/1+3/2+5/3+8/5+13/8+...,求此序列前N项和的简单解法,,#include<stdio.h>#include<stdlib.h>double print_s(int a){double p1[50],p2[50],Sn[50];int i = 0;p1[0] = 2;p2[0] =
include "stdio.h"int main(int argc,char *argv[]){ int N,i,a,b;double s,t;printf("Enter N(int N>0)...\nN=");if(scanf("%d",&N)==1 && N>0){ for(a=2,b=1,s=i=0;i<N;i++)s+=a/(b+0.0),a+=b,b=a-b;printf("s(%d)≈%.4f\n",N,s);} else p...
include <stdio.h>int main() {int n,k,x0,x,y0,y,t;while(scanf("%d",&n) == 1) {x0 = 1,x = 1,y0 = 0,y = 1;for(k = 1;k <= n;k++) {t = x0;x0 = x;x = t + x0;t = y0;y0 = y;y = t + y0;printf("%d/%d ",x,y);}printf("\n");}...
//从第3项开始,分子是前两项分子之和 sum+=b/a; ai=aj; bi=bj; aj=a; bj=b; } printf("前%d项的和= %.2f\n",N,sum); return 0;}示例运行结果:2 前2项的和= 3.50 20 前20项的和= 32.66 ...
这个数列的通项是Fibonacci数列从第二项开始的后一项与前一项的比,所以可以编写一函数产生Fibonacci数列的第n-1项、第n项和第n+1项存于一static int数组中,返回第n+1与第n项的比值浮点数,在主函数中累加求和并输出。n由键盘输入。include <stdio.h> double Fib(void){ static x[3]={0,1,...
PTA(浙⼤版《C语⾔程序设计(第3版)》题⽬集)习题4-3 求分数序列前N项和 (15 分)本题要求编写程序,计算序列 2/1+3/2+5/3+8/5+… 的前N项之和。注意该序列从第2项起,每⼀项的分⼦是前⼀项分⼦与分母的和,分母是前⼀项的分⼦。输⼊格式:输⼊在⼀⾏中给出⼀个正...