NCERT solutions for CBSE and other state boards is a key requirement for students. Doubtnut helps with homework, doubts and solutions to all the questions. It has helped students get under AIR 100 in NEET & IIT JEE. Get PDF and video solutions of IIT-JEE Mains & Advanced previous year pap...
NCERT solutions for CBSE and other state boards is a key requirement for students. Doubtnut helps with homework, doubts and solutions to all the questions. It has helped students get under AIR 100 in NEET & IIT JEE. Get PDF and video solutions of IIT-JEE Mains & Advanced previous year pap...
1.\int_0^{\pi/4} \sec^2 (x)dx=\ a) \ 0 \ \ \ \ \ b) \ 1 \ \ \ \ \ c) \ 2\sqrt 2 \ \ \ \ \ d) \ -1 \ \ \ \ e) \ 2 2. \int_1^{4} (2+\sqrt x)dx=\ a) 32/3 \ \ \ \ \ b) \ 22/3 \ \ \ \ \ c) \ 29/6 \ \ \ \ \ d) \ 2...
Answer to: Integrate: \int xe^x dx By signing up, you'll get thousands of step-by-step solutions to your homework questions. You can also ask your...
$$ \int x ^ { 2 } e ^ { 2 x } d x = \frac { 1 } { 2 } \int x ^ { 2 } d e ^ { 2 x } = \frac { 1 } { 2 } ( x ^ { 2 } e ^ { 2 x } - 2 \int x e ^ { 2 x } d x ) $$ $$ = \frac { 1 } { 2 } ( x ^ { 2 } e ^...
解析 【解析】 $$ \int 2 x e ^ { \frown } x d x = 2 \int x d e ^ { \frown } x = 2 x e ^ { 人 } x - 2 \int e ^ { \frown } x d x = 2 x e ^ { \frown } x - 2 $$ $$ e \uparrow x + C $$ ...
Answer to: Solve : \int x^3 dx/\sqrt {x^2 - 3} . By signing up, you'll get thousands of step-by-step solutions to your homework questions. You can...
D−ea/x+c Evaluate∫x−1x2exdx View Solution Evaluate:∫e2x1+exdx View Solution Evaluate:∫ex(1−x)2(1+x2)2dx View Solution Evaluate:∫ex(x−12x2)dx View Solution 4.Evaluate:∫ex(x−1x2)dx View Solution Evaluate:∫e2x−2exe2x+1dx ...
NCERT solutions for CBSE and other state boards is a key requirement for students. Doubtnut helps with homework, doubts and solutions to all the questions. It has helped students get under AIR 100 in NEET & IIT JEE. Get PDF and video solutions of IIT-JEE Mains & Advanced previous year pap...
答案tant e-arst-sint 一解析 X=2esint y= e-ant ∴(dy)/(dt)=e^(-cost)⋅(-∞t)=sint⋅e^(-cost) t 复合函数求导 (dx)/(dt)=2e^(sint)⋅(sint)'=2cost⋅e^(sint) ∴(dg)/(dt)=(dy)/(dt)⋅(1t)/(dt)=(dy)/(dt)=(sinte^(cost)dt)/(2arcsinte^(2t)dt t =1/2t...