When you try to open a ZIP file on Windows, a message stating ‘the compressed folder is empty’ pops up. As you know the Zip folder consists of files inside it, the situation of Zip folder being empty can be disappointing. However, this error will not let you unzip the compressed ZIP...
Open Log file and watch "Error: ZipArchive::open(): Using empty file as ZipArchive is deprecated at /var/www/lib/private/Archive/ZIP.php#51" Expected behaviour Open Log file without this error :) Actual behaviour Error: ZipArchive::open(): Using empty file as ZipArchive is deprecated at...
public void CompressFolder(string path, ZipOutputStream zipStream, int folderOffset) { var files = Directory.GetFiles(path); var directories = Directory.GetDirectories(path); //this is where I add the empty directory //code begin if (files.Count() == 0 &&...
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function addFolderToZip($dir, $zipArchive, $zipdir = ''){ if (is_dir($dir)) { if ($dh = opendir($dir)) { //Add the directory if(!empty($zipdir)) $zipArchive->addEmptyDir($zipdir); // Loop through all the files while (($file = readdir($dh)) !== false) { //If...
An I/O error occurred while opening a file to be archived. NotSupportedException sourceDirectoryNamecontains an invalid format. Remarks The directory structure from the file system is preserved in the archive. If the directory is empty, an empty archive is created. This method overload does not...
java: error reading /Users/tarikbozdemir/.m2/repository/io/netty/netty-transport/4.1.67.Final/netty-transport-4.1.67.Final.jar; zip file is empty I have a maven project and I am trying to run my x...
srikanth-lingalacommentedNov 26, 2019 To me the problem looks like you are creating a new file if the file does not existfile.createNewFile(). This will just create an empty file, which is not a valid zip file. You don't have to create an empty file before calling any of zip4j's ...
最大错误是1.4的bug： Error creating bean with name 'entityManagerFactory' defined in class path ...