push(NULL); 29 int nLevelCount = 1; 30 while (true) { 31 TreeNode *pTemp = tree_queue.front(); 32 tree_queue.pop(); 33 if (pTemp == NULL) { 34 if (nLevelCount%2 == 0) { //if the num of level is odd, swap the ive
Given a binary tree, return thezigzag level ordertraversal of its nodes' values. (ie, from left to right, then right to left for the next level and alternate between). For example: Given binary tree[3,9,20,null,null,15,7], 3 / \ 9 20 / \ 15 7 return its zigzag level order t...
103. Binary Tree Zigzag Level Order Traversal Given a binary tree, return the zigzag level order traversal of its nodes' values. (ie, from left to right, then right to left for the next level and alternate between). For example: Given binary tree [3,9,20,null,null,15,7], 代码语言:...
Given a binary tree, return thezigzag level ordertraversal of its nodes' values. (ie, from left to right, then right to left for the next level and alternate between). For example: Given binary tree{3,9,20,#,#,15,7}, 3 / \ 9 20 / \ 15 7 return its zigzag level order travers...
Binary Tree Zigzag Level Order Traversal Given a binary tree, return thezigzag level ordertraversal of its nodes' values. (ie, from left to right, then right to left for the next level and alternate between). For example: Given binary tree{3,9,20,#,#,15,7},...
treeNode.isEmpty()) { TreeNode curNode = treeNode.poll(); int curLevel = nodeLevel.poll(); if (curNode != null) { if (ans.size() <= curLevel) { ans.add(new ArrayList<>()); } if ((curLevel % 2) == 0) { ans.get(curLevel).add(curNode.val); } else { ans.get(cur...
Binary Tree Zigzag Level Order Traversal Given a binary tree, return thezigzag level ordertraversal of its nodes' values. (ie, from left to right, then right to left for the next level and alternate between). For example: Given binary tree{3,9,20,#,#,15,7},...
levelTraversal(root->right, level+1, !leftToRight, result); } }; 2. 迭代解法 // 迭代解法 classSolution{ public: vector<vector<int>> zigzagLevelOrder(TreeNode* root) { vector<vector<int> > result; if(!root)returnresult;
103. Binary Tree Zigzag Level Order Traversal 58b6ace olsen-blue reviewed Mar 2, 2025 View reviewed changes 103/step3.cpp vector<TreeNode*> current_level_nodes = {root}; while (!current_level_nodes.empty()) { vector<TreeNode*> next_level_nodes; level_ordered_vals.push_back({...
103. Binary Tree Zigzag Level Order Traversal.md node = nodes[i] values.append(node.val) first, second = access_orders[level % 2] first_node = getattr(node, first) nodchip Feb 27, 2024 リフレクション的な機能は極力使用しないほうが良いと思います。理由は、コンパイル時の静...