说明：这一段时间用Matlab做了LDPC码的性能仿真，过程中涉及了大量的矩阵运算，本文记录了Matlab中矩阵的...
Matlab - zero padding in fft, Let h be a 5x5 matrix, why does zero-padding using fft2 as in H = fft2(h,250,250); not give the same result as using padarray manually, as in H = …
A few ideas though I'm sure others can give a fuller more precise answer. I have done a fair bit of work with the fft, but I don't have a background in it so I have only learned it on a "need to know" basis for my work.
First off, thanks for taking the time to respond. I just tried this out and it's basically what I was doing before but now instead of concatenating two vectors together (the truncated trace_to_offset and zeros()), I'm just assigning directly the truncated trace. I'm not sure ...
'zeropad']\n" "\n" "Nota Bene:\n" " * You can use negative values of n to cut planes off the edges\n" " of a dataset. At least one plane must be added/removed\n" " or the program won't do anything.\n" " * Anat parent and Talairach markers are NOT preserved in the\n...
MATLAB Online에서 열기 I do not understand your line about "does not touch time with sym then forgot". 테마복사 c = a; c(a == sum(a) - sum(b)) = 0; You might perhaps want to describe the variable possibilities in more detail if the above is not the answer....
Open in MATLAB Online hello , here is Newton's method to solve the nonlinear equations, but when I solve the following equation system including 3 unknowns x1,x2,x3 equation 1:x1-pi/4*((2.5e+13-x2^2)*0.6^5/(0.0107*0.883*518.35*278*90000))^0.5- pi/4*((2.5e+13-x3^2)*0.6^5...
There are a few reasons why you might want to zero pad time-domain data. The most common reason is to make a waveform have a power-of-two number of samples. When the time-domain length of a waveform is a power of two, radix-2 FFT algorithms, which are extremely efficient, can be ...
Error using syms: division by zero How to Get Best Site Performance Select the China site (in Chinese or English) for best site performance. Other MathWorks country sites are not optimized for visits from your location.
MATLAB Online에서 열기 clearall clc closeall y = 0.5; u = 0.25; symsn t fun = @(t) (-u + y-2/pi*symsum(1/n*sin(n*pi*(1-y))*exp(-(n*pi)^2*t),n,1,inf)); fzero(fun,0) I want to find the root of the following (variable: t). I get the following error...