去年:year(today())-1,例如今年是2021年,那么year(today())-1 = 2020年。 创建相关的年初、末的参数: I've created (measures) for relative variable year start and end e.g. This year Var TY Start = Date(Year(Today()),01,31) Var TY End = Date(Year(Today()),12,31) Last Year Var ...
範例 下列範例會傳回 2007。 DAX =YEAR("March 2007") 範例- 運算式結果為日期 描述 下列範例會傳回今天日期的年份。 DAX =YEAR(TODAY()) 相關內容 日期和時間函數 HOUR 函式 MINUTE 函式 YEAR 函式 SECOND 函式 意見反映 此頁面有幫助嗎? 是否...
Today, it is also our children of the world: we sing ah, jump ah, put all the troubles in the side to ignore, in the heart very happy, very happy to eat the family reunion dinner, our whole family sitting around a round table. The food on the table is rich: golden chicken, red ...
YTD = IF(YEAR('YourTable'[app_date]) = YEAR(TODAY()), 1, 0) YTDPY = IF(YEAR('YourTable'[app_date]) = YEAR(TODAY()) - 1, 1, 0) View solution in original post Message 4 of 5 155 Views 0 Reply v-zhengdxu-msft Community Support Mark as New Bookmark Subscribe Mute...
Define per year. per year synonyms, per year pronunciation, per year translation, English dictionary definition of per year. Adv. 1. per year - by the year; every year ; "he earned $100,000 per annum"; "we issue six volumes per annum" p.a., per annum, an
DAX has provided many timing intelligence functions, among which people use the DATESYTD function quite frequently. So today, we can discuss how we calculate the year-to-date (YTD) accumulated figure. In the data source, there are two tables. The fact table contains three months sales data fo...
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LASTYEARsalestotal = CALCULATE( SUM ('GROUP'[salestotal]); FILTER ( ALLSELECTED ( 'GROUP'); VALUE('GROUP'[Year]) = Year ( today())-1 && VALUE('GROUP'[Week]) = WEEKNUM(TODAY()) )) TIA for replying Labels: Need Help Message 1 of 17 1,896 Views 0 Reply All...
Happy New Year from Power BI Desktop! Power BI 2 janvier, 2020parSujata Narayana Happy New Year! In honor of the new year, our team put together this fun video where we reveal what makes Power BI what it is today! Enjoy! » En savoir plus ...
Dimdate = VAR x = YEAR( TODAY() ) RETURN CALENDAR( DATE( 2012, 1, 1), DATE( x, 12, 31 ) ) Best regards,Lionel Chen If this post helps, then please consider Accept it as the solution to help the other members find it more quickly. Message 9 of 9 1,886 Views 1 Reply...