1 TypeError: is_leap_year() takes 0 positional arguments but 1 was given 问题分析: 报错的意思是:is_leap_year()这个函数不需要参数,但是函数却被传递了一个参数。 掉头检查代码,会发现: 1 def is_leap_year(): 这里出了问题,我们对其进行修改: 1 def is_leap_year(year): 再次运行代码,成功...
deftest_exceptional_century(self):self.assertIs(is_leap_year(2400),True) 开发者ID:leovieira20,项目名称:exercismpython,代码行数:2,代码来源:leap_test.py 示例3: test_leap_year ▲点赞 3▼ deftest_leap_year(self):self.assertIs(is_leap_year(1996),True) 开发者ID:leovieira20,项目名称:exercis...
(Write a function that takes in a year and returns ‘True’ or ‘False’ whether that year is a leap year. In the Gregorian calendar, three conditions are used to identify leap years:) The year can be evenly divided by 4, is a leap year, unless: The year can be evenly divided by ...
elif year%4==0:return True else:return False def main():month,day,year=input("Please Enter a date in the form month,day,year like 12,31,2012:") if valid(month,day,year):print "The date is valid!"if leap(year):print "The year is leap!"else:print "The year is not leap!"
To check whether a year is a leap year or not, you need to check the following: 1) If the year is evenly divisible by 4, go to step 2. Otherwise, the year is NOT leap year. 2) If the year is evenly divisible by 100, go to step 3. Otherwise, the year is a leap year. 3...
n=int(input("enter year:")) if((n%4==0 and n%400==0) or n%100!=0): print(n,"is leap year") else: Print(n,"is not a leap year") #pythoncode 12th May 2021, 4:36 AM P.Maheswari 0 Weitao Sun. Here is a simple solution https://code.sololearn.com/cOgB9UfjI1vp 10th...
python中函数名is_leap_year python中函数名可以有数字吗 1.函数 函数就是一段具有特点功能的、可重用的语句组。 在Python中函数是以关键词 def 开头,空格之后连接函数名和圆括号(),最后一个冒号:结尾。 函数名只能包含字符串、下划线和数字且不能以数字开头。虽然函数名可以随便起,但我们给函数起名字还是要尽量...
// Golang program to check given year is a// leap year or notpackagemainimport"fmt"funcmain() {varyearint=0fmt.Printf("Enter number: ") fmt.Scanf("%d",&year)if( (year%4==0&&year%100!=0)||(year%4==0&&year%100==0&&year%400==0) ){ fmt.Printf("Entered year is leap year...
Python| Pandas DatetimeIndex.is_leap_year(1) Pandas DatetimeIndex.is_leap_year Pandas 是一个 Python 数据分析库,提供了 DataFrame、Series 等多种数据结构,使数据处理更加方便快捷。Pandas 中的 DatetimeIndex 可以方便地处理时间序列数据,其中包括判断一个年份是否为闰年。
用法: Series.dt.is_leap_year日期是否屬於閏年的布爾指示符。閏年是一個有 366 天(而不是 365 天)的年份,其中包括 2 月 29 日作為閏日。閏年是四的倍數,但能被 100 整除但不能被 400 整除的年份除外。返回: 係列或ndarray 指示日期是否屬於閏年的布爾值。例子:...