使用n√ax=axnaxn=axn,将√x2+2x−1x2+2x-1重写成(x2+2x−1)12(x2+2x-1)12。 y=(x2+2x−1)12y=(x2+2x-1)12 在等式两边同时取微分 ddx(y)=ddx((x2+2x−1)12)ddx(y)=ddx((x2+2x-1)12) yy对xx的导数为y'′。
( x^(1/2)-y^(1/2)=1) Differentiate both sides of the equation. ( d/(dx)(x^(1/2)-y^(1/2))=d/(dx)(1)) Differentiate the left side of the equation. ( -d/(dx)[y]1/(2y^(1/2))+1/(2x^(1/2))) Since ( 1) is constant with respect to ( x), the derivative...
代数输入 三角输入 微积分输入 矩阵输入 y=arcsin(x) 求解x 的值 x=sin(y) ∣y∣≤2π 求解y 的值 y=arcsin(x) ∣x∣≤1 图表
Solve the separable differential equation: 5x-4y Square root of{x^2+1} dy/dx=0. \frac{dy}{dx} = 20 - \frac{y}{x} Solve using Separable Equations. Find the solution for y(2). Find the general solution for the following separable differential equations.\(a)\ \dfrac{dy}{dt} =...
Graph x^2+(y-3 square root of 2x)^2=1x2+(y−3√2x)2=1x2+(y-32x)2=1 Graph. x2+(y−3√2x)2=1x2+(y-32x)2=1x2+(y−3√2x)2=1x2+(y-32x)2=1( ) | [ ] √ ≥ 7 8 9 ≤ 4 5 6 ...
代数输入 三角输入 微积分输入 矩阵输入 y=arcsin(sin(x)) 求解x 的值 x=π+2πn1−y,n1∈Z x=y+2πn2,n2∈Z,∣y∣≤2π 求解y 的值 y=arcsin(sin(x)) 图表
Answer to: Evaluate the integral. integral_{-square root {1 - y^2}}^{square root {1 - y^2}} (x^2 + y^2) dx By signing up, you'll get thousands of...
Solve the following initial value problem for y as a function of x: x {dy} / {dx} = square root {x^2 -25}, x greater than or equal to 5, y (5) = 5. Solve the initial value problem for y as a function of x: x^2 - 9 {d y} /...
After watching all the videos of the famous Standford's CS231n course that took place in 2017, i decided to take summary of the whole course to help me to remember and to anyone who would like to know about it. I've skipped some contents in some lectures as it wasn't important to ...
Uses SiLU activation, approx 2x faster thandm_nfnet_f0and 50% faster thannfnet_f0sw/ 1/3 param count IntegrateHugging Face model hubinto timm create_model and default_cfg handling for pretrained weight and config sharing (more on this soon!) ...