解析 5 \left| x-3 \right|=-\left| y-2 \right|,\left| x-3 \right|+\left| y-2 \right|=0,∵\left| x-3 \right|\geqslant 0,\left| y-2 \right|\geqslant 0,∴\left| x-3 \right|=0,\left| y-2 \right|=0,x=3,y=2,x+y=5....
相关知识点: 试题来源: 解析 -4. 由题意得:\left| x-3 \right|+{{(y-2)}^{2}}=0,可得x-3=0,y-2=0,解得:x=3,y=2,则原式={{x}^{2}}-4xy+4{{y}^{2}}-{{x}^{2}}+{{y}^{2}}=-4xy+5{{y}^{2}}=-24+20=-4....
=\left( {{x}^{2}}-6xy+9{{y}^{2}}-7{{y}^{2}}+7{{x}^{2}}+4xy+2{{x}^{2}}-2{{y}^{2}}-xy \right)\div \left( -\frac{1}{2}x \right)=\left[ \left( {{x}^{2}}+7{{x}^{2}}+2{{x}^{2}} \right)+\left( -6xy+4xy-xy \right)+\left( 9{{...
若实数x、y满足\left( x y-3 \right)\left( x y \right) 2=0,则x y的值为( ). A. -1或-2 B. -1或2 C. 1或-2 D. 1或2 相关知识点: 试题来源: 解析 D 设t=x+y,则由原方程,得t\left( t-3 \right)+2=0,整理,得\left( t-1 \right)\left( t-2 \right)=0.解...
A. \left( -3, 5 \right) B. \left( 3, 5 \right) C. \left( -3, -5 \right) D. \left( 3, -5 \right) 相关知识点: 试题来源: 解析 B 根据二次函数的顶点式方程y=-2{{\left( x-3 \right)}^{2}}+5知,该函数的顶点坐标是:\left( 3, 5 \right).故选\text{B...
原式=\left( {{x}^{2}}-6xy+9{{y}^{2}}-7{{y}^{2}}+7{{x}^{2}}+4xy+2{{x}^{2}}-2{{y}^{2}}-xy \right)\div \left( -\dfrac{1}{2}x \right)~~~=\left( 10{{x}^{2}}-3xy \right)\div \left( -\dfrac{1}{2}x \right)~~~=-20x+6y,∵10x-3y=10...
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百度试题 结果1 题目如果\left| x-3 \right| \left|y-1\right| =0,那么x-y等于( ) A. -4 B. 4 C. 2 D. -2 相关知识点: 试题来源: 解析 C
百度试题 结果1 题目已知\left| x-2 \right|+\left| y-3 \right|=0,则x+y= . 相关知识点: 试题来源: 解析 5 解:根据题意得,x-2=0,y-3=0 ,解得:x=2,y=3,则x+y=2+3=5.
15.若数a使关于x的不等式组$\left\{\begin{array}{l}{\frac{x-2}{2}≤-\frac{1}{2}x+2}\\{7x+4>-a}\end{array}\right.$有且仅有四个整数解.且使关于y的分式方程$\frac{a}{y-2}$+$\frac{2}{2-y}$=2有非负数解.则所有满足条件的整数a的值之和是( )A.3B.1C.0D.-3