解析 $$ xy=e^{x+y} $$ 两边同时对x求导. $$ y+xy^{\prime}=e^{x+y}\cdot(1+y^{\prime}) $$ $$ y+xy^{\prime}=e^{x+y}+e^{x+y}\cdot y^{1} $$ $$ y^{\prime}= \frac{e^{x+y}-y}{x-e^{x+y}} $$ 反馈 收藏
Answer to: Solve the initial value problem. xy^{\prime} - 3y = 4x \;\;\;\; y(1) = 3 By signing up, you'll get thousands of step-by-step solutions...
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