1 <= queries.length <= 3 * 10^4 queries[i].length == 2 0 <= queries[i][0] <= queries[i][1] < arr.length 题解: class Solution { public: vector<int> xorQueries(vector<int>& arr, vector<vector<int>>& queries) { int n = arr.size(); vector<int> pre(n + 1, 0); vec...
地址https://leetcode-cn.com/problems/xor-queries-of-a-subarray/ 有一个正整数数组 arr,现给你一个对应的查询数组 queries,其中 queries[i] = [Li, Ri]。 对于每个查询 i,请你计算从 Li 到 Ri 的 XOR 值(即 arr[Li] xor arr[Li+1] xor ... xor arr[Ri])作为本次查询的结果。 并返回一个...
3. 1 <= queries.length <= 3 * 10^4 4. queries[i].length == 2 5. 0 <= queries[i][0] <= queries[i][1] < arr.length **/classSolution {/** solution: prefix xor array, * because a^b^a = b, q[l,r] = q[0,r] ^ q[0,l-1], so q[l,r] = prefixXOR[r+1] ^...
1 <= queries.length <= 3 * 10^4 queries[i].length == 2 0 <= queries[i][0] <= queries[i][1] < arr.length 题解: classSolution{ public: vector<int>xorQueries(vector<int>&arr,vector<vector<int>>&queries) { intn=arr.size(); vector...