1) {eq}\int x + 1 dx {/eq} 2) {eq}\int x +1 dx = \int x dx + \int 1 dx {/eq} An integral can be distributed over terms that are added or subtracted. View Video Only Save Timeline Video Course 170K views Integral of {eq}xe^x {/eq} Using the Product Rule...
Evaluate the integral: {eq}\; \int xe^{ax^2} \, \mathrm{d}x {/eq}. Evaluate the Integral: The definite integral of a function is related to the antiderivative and indefinite integral of a function. The relationship between these concepts is will be discussed in the Fundamental Theorem ...
Final Answer Thus, the final result of the integral is: ∫xex2dx=12ex2+C --- Similar Questions Evaluate:∫xex2dx View Solution Free Ncert Solutions English Medium NCERT Solutions NCERT Solutions for Class 12 English Medium NCERT Solutions for Class 11 English Medium ...
Find the indefinite integral. ∫xe−x2dx Integration by u- Substitution: If an integral function is not given in a standard form, then we can express it in a standard form likef′(x)dxby applying u-substitution. We can then integrate the function easily in terms of the substituted vari...
To evaluate the integral of a function which is expressed as a product of two independent functions, sayu⋅v, we have to apply the method of integration by parts. In this method, one of the factors is assumed as the first function(u)and the other as the second function(v). The first...
How do you integrate(x2e2x)dx? https://socratic.org/questions/how-do-you-integrate-x-2e-x-2-dx ∫x2e2xdx=2e2x(x2−4x+8)+CExplanation:I=∫x2e2xdx... How do you find the integral of(ex+e−x1)dx?
https://www.quora.com/What-is-displaystyle-int_0-x-e-x-2-dx What is the upper limit of integration ? I assume the upper limit as infinity. To solve then, substitute x^2=t So, the integral gets simplified to Gamma function form and it is eval...
integral (e^x x)/sqrt(e^x-1) dx For the integrand (e^x x)/sqrt(e^x-1), substitute u = sqrt(e^x-1) and du = e^x/(2 sqrt(e^x-1)) dx:= integral 2 log(u^2+1) du Factor out constants:= 2 integral log(u^2+1) du For the integrand log(u^2+1), ...
I=f(x)=int(-a)^a(xe^(x^2))/(1+x^2)dx so, f(-x)=int(-a)^a(-xe^((-x)^2))/(1+(-x)^2)dx f(-x)=-int(-a)^a(xe^(x^2))/(1+x^2)dx f(-x)=-f(x) So, it is odd thus, I=0
Answer to: Find dy/dx : y=xe^{-x}sec x By signing up, you'll get thousands of step-by-step solutions to your homework questions. You can also...