[(x+2.5)^2-4.5^2][(x+2.5)^2-1.5^2]=19 记y=(x+2.5)^2则 y^2-(45/2)y+(27/4)^2=19 (y-45/4)^2=100 y=85/4y=-5/4(此根舍去)x=(-5+√85)/2或x=(-5-√85)/2
解:把方程左边第一个因式与第四个因式相乘,第二个因式与第三个因式相乘,得 (x2+5x-14)(x2+5x+4)=19.设y=(x2+5x-14)+ (x2+5x+4) 2=x2+5x-5,① 则(y-9)(y+9)=19,即y2-81=19.解得y1.2=±10,将y1、y2的值代入①式得,x1.2=-5±√852,x3.4=...
(GX2CrNiMoN26-7-4)热轧板;依厚度不同又有1.4469 (GX2CrNiMoN26-7-4)薄钢板_1.4469 (GX2CrNiMoN26-7-4)中板_1.4469 (GX2CrNiMoN26-7-4)厚板_1.4469 (GX2CrNiMoN26-7-4)特厚板之说;千奇百怪的叫法不仅仅是从常规理解上体现还体现在1.4469 (GX2CrNiMoN26-7-4)化学成分/硬度/密度等性能的...
a,b,c,32,25.5,440.5,442,1,0.5,7,13.5,20,395,279,2,0,7,-14 a,b,c,24,19,366,319,1,2,7,31,24,436.5,306,1,2,7,-14 a,b,c,10,12,270.5,214.5,3.5,0.5,7,14,16.5,319.5,300,2.5,2,7,7 a,b,c,12.5,25.5,257.5,324.5,4,2,7,19.5,24,340.5,317.5,1,2,7,-13 ...
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注意:[(x-2)(x+7)]*[(x+1)(x+4)]=19 (x平方+5x-14)*(x平方+5x+4)=19 设x平方+5x=a,则 (a-14)(a+4)=19 a平方-10a-56=19 a平方-10a-75=0 (a-15)(a+5)=0 所以:a=15 或者 a=-5 则 x平方+5x=15或者 x平方+5x=-5 到这里就会算了撒!
注意:[(x-2)(x+7)]*[(x+1)(x+4)]=19 (x平方+5x-14)*(x平方+5x+4)=19 设x平方+5x=a,则 (a-14)(a+4)=19 a平方-10a-56=19 a平方-10a-75=0 (a-15)(a+5)=0 所以:a=15 或者 a=-5 则 x平方+5x=15或者 x平方+5x=-5 看不懂看下面那个 望采纳哦~
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Investigating superconductivity represents one of the most significant phenomena in the field of condensed matter physics. Our simulations aim to elucidate the structures in the metallic state of Mg1−xMoxB2, which is essential for predicting their sup
x2-4x+4=3+4,即x2-4x+4=7,配方,得(x-2)2=7;故选D. 先把常数项-3移到等式的右边;然后在等式的两边同时加上一次项系数-4的一半的平方. 本题考点:解一元二次方程-配方法. 考点点评:本题考查了解一元二次方程--配方法.配方法的一般步骤:(1)把常数项移到等号的右边;(2)把二次项的系数化为1...