二、已知x =11011, y =-10011,用变形补码计算x-y,同时指出结果是否溢出。相关知识点: 试题来源: 解析 答案: [x]补 = 0011011(或011011),[y]补 =1101101(或101101) [-y]补 =0010011(或010011) [x]补 0 0 1 1 0 1 1 + [-y]补 0 0 1 0 0 1 1 [x-y]补 0 1 0 1 1 1 0 双符号...
已知x=11011和y=-10011,用变形补码计算x+y和x-y,同时指出结果是否溢出。解:[x]补 = ()[y]补 = ()[-y]补 = ()[x+y]补 = [
设x 的补码等于 10111,Y的补码等于 00101,则( X-Y)的补码等于 查看答案
已知x=+11011和y=-10011,用变形补码计算x+y和x-y(或用单符号位补码计算x+y和x-y),同时指出结果是否溢出。 解: [x] 补 = ( )(8位)[y] 补 = ( )(8位)[-y] 补 = ( )(8位) [x+y] 补 = [x] 补 + [y] 补 = ( ) + ( )=( )即x+y=( )(5位数值位),符号位为( ),结果(...
进行Base32编码 二进制 01101000 00101010 01011101 10010100 01101100 10000011 10111000 11101000 10011010 10110011 base32编码分组 01101 00000 10101 00101 11011 00101 00011 01100 10000 01110 11100 01110 10001 00110 10101 10011 转为十进制 13 0 21 5 27 5 3 12 16 14 28 14 17 6 21 19 搜索base32...
y=-10011 解决方案:首先写出X和y的变形补码,然后计算它们的差[X]补码=0011011[y]补码=1101101 [-y]补=0010011 [X-Y]增补=[X]增补+[-Y]增补=0011011+0010011=0101110 ∵运算结果双符号为01不相等∴为正溢出7.用原码阵列乘法器、补码阵列乘法器分别计算x×y。(1)x=11011y=-11111(2)x=-11111y=-11011...
[y]补=00 11011 [-y]补=11 00101 [x-y]补=00 10111+11 00101=11 11100 ∴ x-y= -1 无溢出(3) X=0.11011 Y=-10011 解:先写出x和y的变形补码,再计算它们的差 [x]补=00 11011 [y]补=11 01101 [-y]补=00 10011 [x-y]补=[x]补+[-y]补=00 11011+00 10011=01 01110∵运算结果双...
s1’=11001(25), s2’=01100(12), s3’=11011(27), s4’=10000(16) 然后,做交叉运算,让s1’与s2’,s3’与s4’ 分别交换后三位基因,得 s1’’=11100(28), s2’’=01001(9), s3’’=11000(24), s4’’=10011(19) 这一轮仍然不会发生变异。于是,得第三代种群S3: ...
+03NU3wvEmLBvGOmNGudocWIF/y3VOqyW1byXFLeZxl7s+Y/SthxOYXzu3mF+2/p AgMBAAE= ---END PUBLIC KEY--- 私钥: ---BEGIN RSA PRIVATE KEY--- MIIEogIBAAKCAQB8vXG0ImYhLHvHhpi5FS3gd2QhxSQiU6dQ04F1OHB0yRRQ3NXF 5py2NNDw962i4WP1zpUOHh94/mg/KA8KHNJXHtQVLXMRms+chomsQCwkDi2jbgUa 4jRFN...
X1 11011SY69-0713 18691 1 3001SY69-0713 1569 18681 X1 11011SY69-0713 18691 301 5191SY69-0713 1870 20881 X1 11111SY69-0713 18671 1 3001SY69-0713 1567 18661 X1 11111SY69-0713 18671 301 5211SY69-0713 1868 20881 X1 11211SY69-0713 18651 1 3001SY69-0713 1565 18641 X1 11211SY69...