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for(j=1; j<=n-i; j++) 就是 j 从 1 到 n-i，循环 n - i 次 总的时间复杂度为:(n-1)+(n-2)+……(n-(n-1))= n*(n-1) - (1 + 2 + …… (n - 1))= n*(n-1) - n*(n-1)/2 = n*(n-1)/2
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O(n的平方) i从1到n循环n次， j从1到n循环n次所以他的时间复杂度取最高次就是O(n的平方)
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Great n... Site News Halloween Competition - Winners 31 Oct 2024 SlugGirl Firstly, I’d like to start by saying a huge thank you to every single person who entered our competition. With it being our first one, I’ll be honest, we worried we’d only get two submissions if we were ...
elseif preference eq 5 then //如果路由的preference值不为1不为3不为4,则执行本语句 finish //如果路由的preference值为5,则执行本语句,结束过滤,结果是permit elseif preference eq 6 then //如果路由的preference值不为1不为3不为4不为5,则执行本语句 ...
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count = count + 1 else: print (count, " 大于或等于 5") 执行以上脚本,输出结果如下: 0 小于 5 1 小于 5 2 小于 5 3 小于 5 4 小于 5 5 大于或等于 5 简单语句组 类似if语句的语法,如果你的while循环体中只有一条语句,你可以将该语句与while写在同一行中, 如下所示: ...