Word Ladder - LeetCode 注意点 每一个变化的字母都要在wordList中 解法 解法一:bfs。类似走迷宫,有26个方向(即26个字母),起点是beginWord,终点是endWord。每一次清空完队列ret+1表示走了一步。bfs可以保证是最短路径。 class Solution { public: int ladderLength(string beginWord, string endWord, vector<st...
However, I implemented this BFS but got a TLE. So I adapted adouble-direction BFSwhich may half the running time, and is accepted by the leetcode judge. The algorithm can go as follows. Let start_front be the list of edge words of BFS paths from the start word Let end_front be the...
} public int ladderLength(String beginWord, String endWord, Set<String> wordList) { Queue<Word> queue = new LinkedList<Word>(); queue.offer(new Word(beginWord, 1)); wordList.add(endWord); while (!queue.isEmpty()) { Word w = queue.poll(); if (w.word.equals(endWord)) { return w...
class Solution { public: int ladderLength(string beginWord, string endWord, vector<string>& wordList) { set<string> dicts(wordList.begin(),wordList.end()); // I change the unordered_set to set, and it takes more time to execute the code. if(!dicts.count(endWord)) return 0; queue<...
LeetCode Top Interview Questions 127. Word Ladder (Java版; Medium) 题目描述 AI检测代码解析 Given two words (beginWord and endWord), and a dictionary's word list, find the length of shortest transformation sequence from beginWord to endWord, such that: ...
127. Word Ladder https://leetcode.com/problems/word-ladder/description/ Given two words (beginWord and endWord), and a dictionary's word list, find the length of shortest transformation sequence from be...127. Word Ladder ...127. Word Ladder Given two words (beginWord and endWord), ...
func ladderLength(beginWord string, endWord string, wordList []string) int { // 先把开始单词放入单词列表中,方便后续使用下标处理 wordList = append(wordList, beginWord) startIndex := len(wordList) - 1 // 找到结束单词在单词列表中的下标 endIndex := -1 for i, word := range wordList { ...
[算法分析与设计] leetcode 每周一题: Surrounded Regions 题目链接:https://leetcode.com/problems/surrounded-regions/description/ 题目大意:找出矩阵中被X围住的O,将之翻转成X, 注意位于边界的O即使有3个方向被围住,也不算。(不要求对角线围住) 题目思路: 1. 遍历矩阵的最外围,遇到O,则将之反转成#,...
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LeetCode 0127. Word Ladder单词接龙【Medium】【Python】【BFS】 Problem LeetCode Given two words (beginWordandendWord), and a dictionary's word list, find the length of shortest transformation sequence frombeginWordtoendWord, such that: Only one letter can be changed at a time. ...